
What will be the major product, which can be obtained from the following reaction?
1)
2)
3)
4)
Answer
515.4k+ views
Hint: Nucleophilic substitution reaction: It is a type of an organic reaction in which a nucleophile replaces a nucleophile present in the reactant. The nucleophile which leaves the reactant after reaction is known as the leaving group. Greater the size of the leaving group, more easily it can be replaced by a nucleophile.
Complete answer:
Bimolecular nucleophilic substitution reaction: It is an organic reaction in which attack of nucleophile and removal of leaving group takes place in a single step but the overall reaction depends on both reactant as well as nucleophile. No intermediate is formed in this reaction but it passes through a transition state. As the attack of the nucleophile takes place from the backside, the retention in configuration is observed in the product. Hence, these reactions are inherently stereoselective reactions.
For the given organic reaction, it follows $ S{{N}_{2}} $ reaction mechanism which is discussed as follows:
Step-1: Attack of lone pairs of ammonia to the primary carbon atom.
Step-2: Removal of $ {{H}^{+}} $ ion:
Hence, the final product formed after the reaction is as follows:
Thus, option (1) is the correct answer.
Note:
It is important to note that bimolecular nucleophilic substitution reactions i.e., $ S{{N}_{2}} $ reactions are concerted step reaction i.e., attack of nucleophile and removal of leaving group takes place simultaneously. Hence, less sterically hindered carbon is more preferred for $ S{{N}_{2}} $ reaction mechanism. The order of attack of nucleophile in $ S{{N}_{2}} $ reaction is $ {{1}^{\circ }}>{{2}^{\circ }}>{{3}^{\circ }} $ .
Complete answer:
Bimolecular nucleophilic substitution reaction: It is an organic reaction in which attack of nucleophile and removal of leaving group takes place in a single step but the overall reaction depends on both reactant as well as nucleophile. No intermediate is formed in this reaction but it passes through a transition state. As the attack of the nucleophile takes place from the backside, the retention in configuration is observed in the product. Hence, these reactions are inherently stereoselective reactions.
For the given organic reaction, it follows $ S{{N}_{2}} $ reaction mechanism which is discussed as follows:
Step-1: Attack of lone pairs of ammonia to the primary carbon atom.
Step-2: Removal of $ {{H}^{+}} $ ion:
Hence, the final product formed after the reaction is as follows:
Thus, option (1) is the correct answer.
Note:
It is important to note that bimolecular nucleophilic substitution reactions i.e., $ S{{N}_{2}} $ reactions are concerted step reaction i.e., attack of nucleophile and removal of leaving group takes place simultaneously. Hence, less sterically hindered carbon is more preferred for $ S{{N}_{2}} $ reaction mechanism. The order of attack of nucleophile in $ S{{N}_{2}} $ reaction is $ {{1}^{\circ }}>{{2}^{\circ }}>{{3}^{\circ }} $ .
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