
The major product of the reaction is:
A.
B.
C.
D.
Answer
574.8k+ views
Hint: The above reaction given in the question is a type of elimination reaction. An elimination reaction is a type of reaction in which two substituents are removed from a molecule in either one-step or two-step mechanism. The one-step mechanism is known as the E2 mechanism and two-step mechanism is known as the E1 mechanism.
Complete step by step answer:
In the above reaction in the presence of NaOMe elimination of HBr occurs.
Let us assume that the carbon to which Br is attached is C1, the Carbon just below is C2, As shown in the following diagram:
In the presence of NaOMe, Br will be eliminated from C1 generating a positive charge on C1.
Now, since during an elimination reaction two substituents from adjacent carbon are removed, in addition to Br, there must be an elimination of another substituent as well.
It can be the elimination of H from C2 or elimination of methyl groups from C5. Since the removal of H is easier as compared to removal of the Methyl group, H from C2 will be eliminated. And a negative charge will be generated at C2
This will lead to the formation of a double bond between C1 and C2.
This implies, that the major product of the given reaction will
Thus, option A is the right answer.
Note:
There are three types of organic reactions, namely
-Addition reaction: a molecule gets added to the other molecule. For example, the addition of hydrogen to ethane.
-Elimination reaction: discussed above
-Substitution reaction: a substituent of a molecule gets replaced by another substituent. For example, when chloromethane reacts with NaOH, methanol is formed and Cl gets replaced by the OH group.
Complete step by step answer:
In the above reaction in the presence of NaOMe elimination of HBr occurs.
Let us assume that the carbon to which Br is attached is C1, the Carbon just below is C2, As shown in the following diagram:
In the presence of NaOMe, Br will be eliminated from C1 generating a positive charge on C1.
Now, since during an elimination reaction two substituents from adjacent carbon are removed, in addition to Br, there must be an elimination of another substituent as well.
It can be the elimination of H from C2 or elimination of methyl groups from C5. Since the removal of H is easier as compared to removal of the Methyl group, H from C2 will be eliminated. And a negative charge will be generated at C2
This will lead to the formation of a double bond between C1 and C2.
This implies, that the major product of the given reaction will
Thus, option A is the right answer.
Note:
There are three types of organic reactions, namely
-Addition reaction: a molecule gets added to the other molecule. For example, the addition of hydrogen to ethane.
-Elimination reaction: discussed above
-Substitution reaction: a substituent of a molecule gets replaced by another substituent. For example, when chloromethane reacts with NaOH, methanol is formed and Cl gets replaced by the OH group.
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