Question

The magnetic quantum number of the valence electron of sodium is
 $ A) $ $ 2 $
 $ B) $ $ 3 $
 $ C) $ $ 1 $
 $ D) $ $ 0 $

Answer 1

Hint: the magnetic quantum number is one of four quantum numbers in nuclear physical science. The set is: principle quantum number, azimuthal quantum number, magnetic quantum number, and spin quantum number.

Complete answer:
Sodium has $ 11 $ electrons, so the electron configuration of sodium is $ 1{s^2}2{s^2}2{p^6}3{s^1} $ .
The orbital is $ s $ orbital because the valence electron is in $ 3s $ orbital. So, the azimuthal quantum number is $ 0 $ because s orbital has only $ 1 $ electron.
So, the magnetic quantum number will be $ 0 $ .
Correct answer is option $ (D). $

Additional Information:
-The azimuthal quantum number portrays the state of a given orbital. It is signified by the image ' $ I $ ' and its value is equivalent to the complete number of angular nodes in the orbital. An estimation of the azimuthal quantum number can show either a $ s $ , $ p $ , $ d $ , or $ f $ subshell which differ in shapes.
- For instance, if n = $ 3 $ , the azimuthal quantum number can take on the accompanying qualities – $ 0 $ , $ 1 $ , and $ 2 $ . When $ L = 0 $ , the subsequent subshell is an ' $ S $ ' subshell. Likewise, when $ L = 1 $ and $ L = 2 $ , the subsequent subshells are ' $ p $ ' and ' $ d $ '. In this way, when $ n = 3 $ , the three potential subshells are $ 3s $ ,
 $ 3p $ , and $ 3d $ .
In another model where the estimation of $ n $ is $ 5 $ , the potential estimations of $ I $ are $ 0 $ , $ 1 $ , $ 2 $ , $ 3 $ , and $ 4 $ . Assuming $ L = 3 $ , there are an aggregate of three angular nodes in the atom.

Note:
The plan of electrons in the orbitals of an ion is called its electronic configuration. We portray an electron arrangement with an image that contains pieces of data. The quantity of the foremost quantum shell, $ n $ . The letter that assigns the orbital subshell, $ l $ . A superscript number that assigns the quantity of electrons in the specific subshell.