Question

The list price of an article at a showroom is $ Rs.2000 $ and it is being sold at successive discounts of $ 20\% $ and $ 10\% $ . Its net selling price will be:
 $ \left( a \right){\text{ Rs}}{\text{.1400}} $
 $ \left( b \right){\text{ Rs}}{\text{.1440}} $
 $ \left( c \right){\text{ Rs}}{\text{.1520}} $
 $ \left( d \right){\text{ Rs}}{\text{.1700}} $

Answer 1

Hint: For solving this question we will first find the $ 20\% $ of $ 2000 $ and from this we will have the selling price for the first discount, we just need to subtract it from the list price. And similarly for the second discount also we will do the same. And in the end, we will get the selling price by subtracting the selling price of the first discount from the selling price of the second discount. And in this way, we will solve this question.

Complete step-by-step answer:
 In the question, it is given that the list price of an article at a showroom is $ Rs.2000 $ .
Let us assume $ 20\% $ and $ 10\% $ be the first and second discount respectively.
So now we will calculate $ 20\% $ the list price. And mathematically it can be written as,
 \[ \Rightarrow 20\% {\text{ of 2000}}\]
On removing the percentage we will get the equation as
 \[ \Rightarrow \dfrac{{20}}{{100}} \times {\text{2000}}\]
And on solving the above line, we get
 $ \Rightarrow Rs.400 $
Therefore, the first selling price will be equal to
 $ \Rightarrow Rs.2000 - Rs.400 $
And on solving it we get
 $ \Rightarrow Rs.1600 $
So now we will calculate $ 10\% $ of the first selling price. And mathematically it can be written as,
 \[ \Rightarrow 10\% {\text{ of 1600}}\]
On removing the percentage we will get the equation as
 \[ \Rightarrow \dfrac{{10}}{{100}} \times 1600\]
And on solving the above line, we get
 $ \Rightarrow Rs.160 $
Therefore, the second selling price will be equal to
 $ \Rightarrow Rs.1600 - Rs.160 $
And on solving it we get
 $ \Rightarrow Rs.1440 $
Hence, its net selling price will be $ Rs.1440 $ .
Therefore, the option $ \left( b \right) $ is correct.
So, the correct answer is “Option b”.

Note: This question can also be solved in another way or we can say while solving for the competitive exam we can opt for this method. Since we have a list price already given, so after the discount, the selling price will be given by $ 2000 \times \dfrac{{80}}{{100}} \times \dfrac{{90}}{{100}} $ and on solving it we will get the solution. So this can also be used.