
The liquids $X$ and $Y$ are mixed in the ratio $3:2$ and the mixture is sold at Rs. 11 per liter at a profit of 10%. If the liquid $X$ costs Rs. 2 more per liter than $Y$, the cost of $X$ per liter is (in Rs.):
(A) 9.50
(B) 10.80
(C) 11.75
(D) 11
Answer
588k+ views
Hint: Assume the volume of liquids to be some variable according to the ratio given. Find the total selling price of liquid using Rs. 11 per liter rate. Then determine their cost using the profit percent given. Finally use the cost per liter rate of liquids X and Y and compare it with total cost.
Complete step-by-step answer:
According to the question, the liquids $X$ and $Y$ are mixed in the ratio $3:2$.
Let $3x$ and $2x$ are the respective volumes in which they are mixed. So the total volume of the mixture is $5x$.
Now, this mixture is sold at Rs. 11 per liter. So the total selling price i.e. S.P. is given as:
$ \Rightarrow $S.P. $ = 11 \times 5x = 55x$
And this is sold at 10% profit. So we have:
$ \Rightarrow $C.P. + 10% of C.P. = S.P.
where C.P. is the total cost price.
Putting the value of S.P. and simplifying further, we’ll get:
$ \Rightarrow $C.P. + $\dfrac{{10}}{{100}} \times $ C.P. $ = 55x$
$ \Rightarrow $C.P. + $\dfrac{1}{{10}} \times $ C.P. $ = 55x$
$ \Rightarrow $$\dfrac{{11}}{{10}} \times $ C.P. $ = 55x$
$ \Rightarrow $C.P. $ = 50x$
So we have a total cost price as $50x$.
Further it is given that, liquid $X$ costs Rs. 2 more per liter than $Y$. So the cost price of liquid $X$ is Rs. $a + 2$ per liter and that of liquid $Y$ is Rs. $a$ per liter.
Thus the total cost of $3x$ liter of $X$ and $2x$ liter of $Y$ is given as:
$ \Rightarrow $C.P. $ = 3x\left( {a + 2} \right) + 2xa = 5xa + 6x$
Putting the value of total cost price calculated above, we’ll get:
$
\Rightarrow 5xa + 6x = 50x \\
\Rightarrow 5xa = 44x \\
\Rightarrow a = \dfrac{{44}}{5} = 8.8 \\
$
Thus the cost price of liquid $X$ is $a + 2 = 10.8$.
(B) is the correct option.
Note: Profit or loss is always calculated over cost price and not over selling price. In this problem, the profit percentage was given but cost price was not given. So we were required to find the cost price first to compare the quantities and solve the problem.
If the cost price is more than the selling price, loss is seen. If the selling price is more than the cost price, profit is seen.
Complete step-by-step answer:
According to the question, the liquids $X$ and $Y$ are mixed in the ratio $3:2$.
Let $3x$ and $2x$ are the respective volumes in which they are mixed. So the total volume of the mixture is $5x$.
Now, this mixture is sold at Rs. 11 per liter. So the total selling price i.e. S.P. is given as:
$ \Rightarrow $S.P. $ = 11 \times 5x = 55x$
And this is sold at 10% profit. So we have:
$ \Rightarrow $C.P. + 10% of C.P. = S.P.
where C.P. is the total cost price.
Putting the value of S.P. and simplifying further, we’ll get:
$ \Rightarrow $C.P. + $\dfrac{{10}}{{100}} \times $ C.P. $ = 55x$
$ \Rightarrow $C.P. + $\dfrac{1}{{10}} \times $ C.P. $ = 55x$
$ \Rightarrow $$\dfrac{{11}}{{10}} \times $ C.P. $ = 55x$
$ \Rightarrow $C.P. $ = 50x$
So we have a total cost price as $50x$.
Further it is given that, liquid $X$ costs Rs. 2 more per liter than $Y$. So the cost price of liquid $X$ is Rs. $a + 2$ per liter and that of liquid $Y$ is Rs. $a$ per liter.
Thus the total cost of $3x$ liter of $X$ and $2x$ liter of $Y$ is given as:
$ \Rightarrow $C.P. $ = 3x\left( {a + 2} \right) + 2xa = 5xa + 6x$
Putting the value of total cost price calculated above, we’ll get:
$
\Rightarrow 5xa + 6x = 50x \\
\Rightarrow 5xa = 44x \\
\Rightarrow a = \dfrac{{44}}{5} = 8.8 \\
$
Thus the cost price of liquid $X$ is $a + 2 = 10.8$.
(B) is the correct option.
Note: Profit or loss is always calculated over cost price and not over selling price. In this problem, the profit percentage was given but cost price was not given. So we were required to find the cost price first to compare the quantities and solve the problem.
If the cost price is more than the selling price, loss is seen. If the selling price is more than the cost price, profit is seen.
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