Question

The length of the rectangle with area 54 square centimeters is 9 centimeters. What is the perimeter of the rectangle, in centimeters?

Answer 1

Hint: Area of Rectangle is given by
$A=L \times B$
Where L is the length and B is the Breadth of the rectangle respectively and perimeter (P) is given by$P=2(L+B)$, so here we have to find the breadth of the rectangle.



Complete step-by-step answer:
As we know
$A=L \times B$

We have from question
$A=54$ sq. cm
$L=9$ Cm
$\begin{align}
  & \Rightarrow 54=9\times B \\
 & \Rightarrow B=\dfrac{54\text{ sq. cm}}{9\text{ cm}} \\
 & \Rightarrow B=6\text{ cm} \\
\end{align}$
Now using formula of perimeter
\[\begin{align}
  & \text{P=2(L+B)} \\
 & \Rightarrow \text{P=2(9+6) cm} \\
 & \Rightarrow \text{P=30 cm} \\
 & \\
\end{align}\]
So the perimeter of the rectangle is 30 cm.

Note: unit of area is $cm^2$, while unit of perimeter cm so take care of unit of perimeter.