Question

The length of the rectangle with area 54 square centimeters is 9 centimeters. What is the perimeter of the rectangle, in centimeters?

Answer 1

Hint: Area of Rectangle is given by
$A=L\times B$
Where L is the length and B is the Breadth of the rectangle respectively and perimeter (P) is given by$P=2(L+B)$, so here we have to find the breadth of the rectangle.



Complete step-by-step answer:
As we know
$A=L\times B$

We have from question
$A=54$ sq. cm
$L=9$ Cm
$\begin{array}{rl}& \Rightarrow 54=9\times B\\ & \Rightarrow B={\displaystyle \frac{54\text{ sq. cm}}{9\text{ cm}}}\\ & \Rightarrow B=6\text{ cm}\end{array}$
Now using formula of perimeter
$$\begin{array}{rl}& \text{P=2(L+B)}\\ & \Rightarrow \text{P=2(9+6) cm}\\ & \Rightarrow \text{P=30 cm}\\ & \end{array}$$
So the perimeter of the rectangle is 30 cm.

Note: unit of area is $c{m}^2$, while unit of perimeter cm so take care of unit of perimeter.