Question

The length of a rectangle is 4 meters more than its breadth. What is its perimeter?.

Answer 1

Hint: We are asked to find the perimeter of a rectangle. First, we will find the dimension of the rectangle that means length and breadth. We will assume the breadth as x. So, as we have the length is 4 more than the breadth, so we will get length as 4 + x. Then we know that the perimeter is the sum of all the sides of the rectangle. So, we add both the length and breadth of the rectangle to get our radius.

Complete step-by-step answer:
We are asked to find the perimeter of a rectangle. We are given that the length is 4 more than its breadth. To find the perimeter, we have to first find the dimension of the rectangle. Let us assume that the breadth of the rectangle is x.
Breadth of rectangle = x meters…….(i)
Now, we get the breadth of the rectangle. We will look for the length of the rectangle. We are given that the length of the rectangle is 4 meters more than the breadth. As our breadth is x meters, so 4 meters more than the breadth means 4 more than x. So, the length of the rectangle is 4 more than x.
Length of rectangle = 4 + x meters
Now, we have the length as 4 + x and breadth as x. Now, we will find the perimeter of the rectangle. We know that the perimeter of the rectangle is given as the sum of all the sides.

So, we get the perimeter of the rectangle as,
\[\text{Perimeter of rectangle}=x+4+x+x+4+x\]
\[\Rightarrow \text{Perimeter of rectangle}=4x+4+4\]
On simplifying further, we get,
\[\Rightarrow \text{Perimeter of rectangle}=4x+8\]

Note: As we get the length as 4 + x and breadth as x, then we know that the perimeter of the rectangle is given as 2 (L + B).
\[\text{Perimeter}=2\left( L+B \right)\]
\[\Rightarrow \text{Perimeter}=2\left( x+4+x \right)\]
On solving, we get,
\[\Rightarrow \text{Perimeter}=2\left( 2x+4 \right)\]
\[\Rightarrow \text{Perimeter}=4x+8\]
Remember that 4 more than something means 4 is added to it. 4 more than a thing means we have to multiply 4 with that.