
The length of a rectangle exceeds its breadth by 7 cm. If the length is decreased by 4 cm and breadth is increased by 3, the new rectangle is the same as the area of the original rectangle. Find the length and the breadth of the original rectangle.
Answer
590.4k+ views
Hint: The area of the rectangle is length times its breadth. Solution can be started by assuming the breadth of the rectangle any arbitrary variable.
Complete step-by-step answer:
We are given that the length of a rectangle exceeds its breadth by 7 cm. If the length is decreased by 4 cm and breadth is increased by 3, the new rectangle is the same as the area of the original rectangle.
Let us start by assuming the breadth of original triangle as $x$ i.e.
$b = x$ ….. (1)
The length of original rectangle is 7 more than its breadth, i.e.
$l = x + 7$ ……. (2)
From equation (1) and (2) we get the area of the rectangle as –
$A = l \times b$
$A = (x + 7) \times x$
$A = {x^2} + 7x$ ………… (3)
Now, the lengths and breadth of the rectangle are change as –
Length is decreased by 4 i.e.
New length (L) = Original length +7
$\begin{gathered}
= (x + 7) - 4 \\
= x + 3.............(4) \\
\end{gathered} $
New breadth (B) = Original breadth +3
$ = (x) + 3.......(5)$
The area of the rectangle now becomes –
\[A = L \times B\]
From equation (4) and (5) we have,
\[A = (x + 3) \times (x + 3)\]
Simplifying the above equation we have,
\[A = {x^2} + 3x + 3x + 9\]
\[A = {x^2} + 6x + 9\] ……….. (6)
It is given that the equation area remains the same. Therefore,
From equation (3) and (6) we get,
\[{x^2} + 6x + 9 = {x^2} + 7x\]
Subtracting both sides by \[{x^2}\]
\[6x + 9 = 7x\]
Subtracting both sides by \[6x\] we get,
\[9 = x\]
Therefore, putting the value of x in equation (1) and two we get the length and breadth as follow –
$b = x = 9$ And,
$l = x + 7 = 9 + 7 = 16$
Therefore, the length is 16cm and the breadth is 9cm.
Note: There can be similar questions in which the area instead of being equal it will change. In such cases we form a quadratic equation and solve it by middle term split. Middle term split method is used to split the variables into 2 parts.
Complete step-by-step answer:
We are given that the length of a rectangle exceeds its breadth by 7 cm. If the length is decreased by 4 cm and breadth is increased by 3, the new rectangle is the same as the area of the original rectangle.
Let us start by assuming the breadth of original triangle as $x$ i.e.
$b = x$ ….. (1)
The length of original rectangle is 7 more than its breadth, i.e.
$l = x + 7$ ……. (2)
From equation (1) and (2) we get the area of the rectangle as –
$A = l \times b$
$A = (x + 7) \times x$
$A = {x^2} + 7x$ ………… (3)
Now, the lengths and breadth of the rectangle are change as –
Length is decreased by 4 i.e.
New length (L) = Original length +7
$\begin{gathered}
= (x + 7) - 4 \\
= x + 3.............(4) \\
\end{gathered} $
New breadth (B) = Original breadth +3
$ = (x) + 3.......(5)$
The area of the rectangle now becomes –
\[A = L \times B\]
From equation (4) and (5) we have,
\[A = (x + 3) \times (x + 3)\]
Simplifying the above equation we have,
\[A = {x^2} + 3x + 3x + 9\]
\[A = {x^2} + 6x + 9\] ……….. (6)
It is given that the equation area remains the same. Therefore,
From equation (3) and (6) we get,
\[{x^2} + 6x + 9 = {x^2} + 7x\]
Subtracting both sides by \[{x^2}\]
\[6x + 9 = 7x\]
Subtracting both sides by \[6x\] we get,
\[9 = x\]
Therefore, putting the value of x in equation (1) and two we get the length and breadth as follow –
$b = x = 9$ And,
$l = x + 7 = 9 + 7 = 16$
Therefore, the length is 16cm and the breadth is 9cm.
Note: There can be similar questions in which the area instead of being equal it will change. In such cases we form a quadratic equation and solve it by middle term split. Middle term split method is used to split the variables into 2 parts.
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