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The length, in inches of a box is 3 inches less than twice its width in inches. Which of the following gives the length, \[l\] inches in terms of the width, \[w\] inches of the box?
A.\[l = \dfrac{1}{2}w + 3\]
B.\[l = w + 3\]
C.\[l = w - \dfrac{3}{2}\]
D.\[l = 2w - 3\]
E.\[l = w - \dfrac{3}{2}\]

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Last updated date: 20th Jun 2024
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Answer
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Hint: Here, we will assume that width is \[b\] and length is \[l\]. Then we will first find the twice its width and then subtract it by 3. Then we will take it equal to \[l\] to find the required value.

Complete step-by-step answer:
We are given that the length, in inches of a box, is 3 inches less than twice its width in inches.
Let us assume that width is \[b\] and length is \[l\].
Using the given conditions, we will first find the twice of the width, we get
\[ \Rightarrow 2w\]
Subtracting the above expression by 3, we get
\[ \Rightarrow 2w - 3\]
Taking the above expression equal to \[l\] to find the required value, we get
\[ \Rightarrow l = 2w - 3\]
Hence, option D is correct.

Note: The first dimension to measure is length. Length is always the longest side of the box that has a flap. The next dimension is width. The width side also has a flap, but is always the side shorter than the length. Measure the height of the package. Height is the only dimension without a flap. Measure the standing side of the box from top to bottom. The height measurement does not include flaps.