
The least count of vernier calipers is 0.01cm, and if the zero mark of the vernier scale is to the right of zero of the main scale and the vernier coincides with 7 when the jaws are in contact, then the zero error is_______cm.
$
{\text{A}}.{\text{ + 6}} \times {\text{0}}{\text{.01}} \\
{\text{B}}{\text{. + 7}} \times {\text{0}}{\text{.01}} \\
{\text{C}}{\text{. - 7}} \times {\text{0}}{\text{.01}} \\
{\text{D}}{\text{. - 6}} \times {\text{0}}{\text{.01}} \\
$
Answer
496.5k+ views
Hint: The zero error can be found by multiplying the least count of the vernier with the number of divisions which is coinciding with the zero of the main scale. It depends on whether it is to the left or right that zero error needs to be added or subtracted from a reading.
Step by step solution:
Vernier calipers are an instrument used to accurately measure lengths. This precision up to which certain length can be measured using it is called least count. The least count of given vernier calipers is 0.1 cm.
Zero error is the situation when the instrument gives a measurement when the jaws are closed and actual measurement should be zero.
Zero errors are of two types:
a.)Positive zero error: When the instrument gives a positive value when its jaws are closed, it is called the positive zero error. It needs to be deducted from the final reading.
b.)Negative zero error: When the instrument gives a negative value when its jaws are closed, it is called the negative zero error which needs to be added to the final value.
The zero error of vernier calipers equal to the product of least count with the value of division with which the zero coincides when jaws are closed.
For the given instrument,
$L.C. = 0.01cm$
Division coinciding with zero = 7
The zero of the vernier scale is to the right of the zero of the main scale, this means it is positive zero error and must be subtracted from the final reading.
Therefore, the zero error
$ = - 7 \times 0.01cm$
And the correct answer is option C.
Note: The type of zero error needs to be calculated carefully. If zero vernier calipers are to the right of zero of the main scale then zero error needs to be added to the final reading. It is necessary to find zero error to ensure accuracy of measurement.
Step by step solution:
Vernier calipers are an instrument used to accurately measure lengths. This precision up to which certain length can be measured using it is called least count. The least count of given vernier calipers is 0.1 cm.
Zero error is the situation when the instrument gives a measurement when the jaws are closed and actual measurement should be zero.
Zero errors are of two types:
a.)Positive zero error: When the instrument gives a positive value when its jaws are closed, it is called the positive zero error. It needs to be deducted from the final reading.
b.)Negative zero error: When the instrument gives a negative value when its jaws are closed, it is called the negative zero error which needs to be added to the final value.
The zero error of vernier calipers equal to the product of least count with the value of division with which the zero coincides when jaws are closed.
For the given instrument,
$L.C. = 0.01cm$
Division coinciding with zero = 7
The zero of the vernier scale is to the right of the zero of the main scale, this means it is positive zero error and must be subtracted from the final reading.
Therefore, the zero error
$ = - 7 \times 0.01cm$
And the correct answer is option C.
Note: The type of zero error needs to be calculated carefully. If zero vernier calipers are to the right of zero of the main scale then zero error needs to be added to the final reading. It is necessary to find zero error to ensure accuracy of measurement.
Recently Updated Pages
Master Class 11 Accountancy: Engaging Questions & Answers for Success

Glucose when reduced with HI and red Phosphorus gives class 11 chemistry CBSE

The highest possible oxidation states of Uranium and class 11 chemistry CBSE

Find the value of x if the mode of the following data class 11 maths CBSE

Which of the following can be used in the Friedel Crafts class 11 chemistry CBSE

A sphere of mass 40 kg is attracted by a second sphere class 11 physics CBSE

Trending doubts
10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

State and prove Bernoullis theorem class 11 physics CBSE

What organs are located on the left side of your body class 11 biology CBSE

Write down 5 differences between Ntype and Ptype s class 11 physics CBSE
