
The LCM and HCF of two numbers are 960 and 8 respectively. If one of the numbers is 64, then the other number is
A.60
B.120
C.240
D.480
Answer
594.3k+ views
Hint: The product of 2 numbers is always equal to the product of their Highest common factor (HCF) and Least common multiple (LCM).
Complete step-by-step answer:
It is given that the HCF and LCM of two numbers are 960 and 8 respectively. One of the numbers is 64.
Let the other number be $x$ .
Since
$HCF \times LCM = $ Product of 2 Numbers
$ \Rightarrow 960 \times 8 = 64 \times x$
$ \Rightarrow \dfrac{{960 \times 8}}{{64}} = x$
$ \Rightarrow x = 120$
Thus the other number is 120.
Note: The vice versa is also always true. The product of the 2 numbers will always give the product of HCF and LCM so we can find them if either is given.
Complete step-by-step answer:
It is given that the HCF and LCM of two numbers are 960 and 8 respectively. One of the numbers is 64.
Let the other number be $x$ .
Since
$HCF \times LCM = $ Product of 2 Numbers
$ \Rightarrow 960 \times 8 = 64 \times x$
$ \Rightarrow \dfrac{{960 \times 8}}{{64}} = x$
$ \Rightarrow x = 120$
Thus the other number is 120.
Note: The vice versa is also always true. The product of the 2 numbers will always give the product of HCF and LCM so we can find them if either is given.
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