
The Independence day of India in 2007 was celebrated on a Wednesday, then Children’s day in 2008 was celebrated on a
A. Friday
B. Saturday
C. Sunday
D. Monday
Answer
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Hint:In the question Independence day that is 15 august and children’s day that is 14 November is given. To solve this question, firstly we will find the number of odd days in the different months. Then we will calculate the numbers of days between the 15 August 2007 and 14 November 2008. We will have to assign numbers from 0 to 6 to the days of the week for the calculation. Final answer is calculated by dividing the number of odd days by 7 and the day will be counted by considering Wednesday as the first day.
Complete answer:
The number of odd days in the month can be found by dividing the number of days in the month by 7, hence the number of odd days in the following months are:
The number of odd days in January are 3.
The number of odd days in February are 0 for normal year and 1 for leap year.
The number of odd days in March are 3.
The number of odd days in April are 2.
The number of odd days in May are 3.
The number of odd days in June are 2.
The number of odd days in July are 3.
The number of odd days in August are 3.
The number of odd days in September are 2.
The number of odd days in October are 3.
The number of odd days in November are 2.
The number of odd days in December are 3.
Now, we will assign numbers for all the week days.
0 for Sunday
1 for Monday
2 for Tuesday
3 for Wednesday
4 for Thursday
5 for Friday
6 for Saturday
The number of days from 15 August 2007 to 14 November 2008 can be counted as,
The total number of days will be 65.
Now on dividing the number 65 by 7 We get the number 2.
For Wednesday the number assigned is 3. On adding 2 to this will give 5. For the number 5 assigned day is Friday.
Therefore, Children’s day in 2008 was celebrated on Friday and option A is the correct answer.
Note:Before solving the problem, always check for the year whether it is leap year or normal year because the number of odd days are different for the leap and normal year. Also always do the calculation by considering the given day as the first day and then adding the remainder in the assigned number to the day.
Complete answer:
The number of odd days in the month can be found by dividing the number of days in the month by 7, hence the number of odd days in the following months are:
The number of odd days in January are 3.
The number of odd days in February are 0 for normal year and 1 for leap year.
The number of odd days in March are 3.
The number of odd days in April are 2.
The number of odd days in May are 3.
The number of odd days in June are 2.
The number of odd days in July are 3.
The number of odd days in August are 3.
The number of odd days in September are 2.
The number of odd days in October are 3.
The number of odd days in November are 2.
The number of odd days in December are 3.
Now, we will assign numbers for all the week days.
0 for Sunday
1 for Monday
2 for Tuesday
3 for Wednesday
4 for Thursday
5 for Friday
6 for Saturday
The number of days from 15 August 2007 to 14 November 2008 can be counted as,
August 2007 | 16 |
September 2007 | 2 |
October 2007 | 3 |
November 2007 | 2 |
December 2007 | 3 |
January 2008 | 3 |
February 2008 | 1 |
March 2008 | 3 |
April 2008 | 2 |
May 2008 | 3 |
June 2008 | 2 |
July 2008 | 3 |
August 2008 | 3 |
September 2008 | 2 |
October 2008 | 3 |
November 2008 | 14 |
The total number of days will be 65.
Now on dividing the number 65 by 7 We get the number 2.
For Wednesday the number assigned is 3. On adding 2 to this will give 5. For the number 5 assigned day is Friday.
Therefore, Children’s day in 2008 was celebrated on Friday and option A is the correct answer.
Note:Before solving the problem, always check for the year whether it is leap year or normal year because the number of odd days are different for the leap and normal year. Also always do the calculation by considering the given day as the first day and then adding the remainder in the assigned number to the day.
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