Question

The income of a man has increased in the ratio of 10:11. If the increase in his income is Rs. 600 per month. Find his new income.

Answer 1

Hint: We first take $x$ as the ratio constant which gets multiplied to the given ratios to find his old and new income. We find the difference between the incomes to equate it with 600 as that is the difference. From that we multiply with 11 to find his new income.

Complete step by step solution:
The income of a man has increased in the ratio of 10:11. We take $x$ as the ratio constant.
Therefore, we can get that the previous income was $10x$ and the revised income is $11x$.
The increase in his income is Rs. 600 per month.
The increase algebraically is $11x-10x=x$.
Creating the equation, we get $x=600$.
We have to find his new income which is equal to $11x$.
We multiply 11 to the value of 600 to find his new income.
His new income is $600\times 11=6600$ Rs.
The new income of the man is Rs. 6600.

Note: We can also solve the problem without taking any constant. The ratio difference of 1 unit is equal to 600. We need to find the value for 11 unit which gives $600\times 11=6600$. The same process where the unit value gives 600.