The Hinsberg test of a compound, ${{C}_{5}}{{H}_{14}}{{N}_{2}}$ produces a solid that is insoluble in 10% NaOH. This solid derivative dissolves in 10% aqueous sulphuric acid. Which of the following would best describe these facts?(A) $N{{H}_{2}}C{{H}_{2}}C{{H}_{2}}N{{\left( C{{H}_{3}} \right)}_{2}}$ (B) ${{\left( C{{H}_{3}} \right)}_{2}}NC{{H}_{2}}C{{H}_{2}}NHC{{H}_{3}}$ (C) $N{{H}_{2}}C{{H}_{2}}C{{\left( C{{H}_{3}} \right)}_{2}}C{{H}_{2}}N{{H}_{2}}$ (D) ${{\left( C{{H}_{3}} \right)}_{2}}NC{{H}_{2}}N{{\left( C{{H}_{3}} \right)}_{2}}$

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Vedantu Content Team · Accepted Answer

Hint: Heisenberg’s test is used to differentiate between primary amine, secondary amine and tertiary amine. The reagent used for this reaction is phenyl sulfonyl chloride which can be prepared at the time of the reaction and can be a compound or a mixture of compounds.Complete answer:Let us discuss the Heisenberg’s test in detail,This test is primarily used to differentiate within primary, secondary and tertiary amines. The amines here, acts as a nucleophile which attacks an electrophile i.e. Heisenberg’s reagent (benzene sulphonyl chloride).Primary amine-When Heisenberg’s reagent reacts with primary amine it gives a sulphonamide product which is soluble in alkali.Secondary amine-The reaction of Heisenberg’s reagent with secondary amine gives a sulphonamide which is insoluble in alkali but is water-soluble in the acid.Tertiary amine-There is no reaction in between tertiary amine and Heisenberg’s reagent.Thus, this test is used for the differentiation of amines on the basis of the solubility of the obtained product in alkali.Illustration-In the given illustration we can see that,Option (A) and (C) are primary amines; option (D) is tertiary amine. Hence, in accordance with the above given explanation only option (B) will satisfy the criteria as it is a secondary amine.We can easily specify this by the reactions as follows,

Therefore, option (B) is correct.Note: The terms used to classify amines as primary, secondary and tertiary are derived in very different form than that of other classifications as of alcohols or alkyl halides. During the classification of amines, these terms are used to refer to the number of alkyl substitutes directly bonded to N-atom.

The Hinsberg test of a compound, C5H14N2 produces a solid that is insoluble in 10% NaOH. This solid derivative dissolves in 10% aqueous sulphuric acid. Which of the following would best describe these facts?(A) NH2CH2CH2N(CH3)2 (B) (CH3)2NCH2CH2NHCH3 (C) NH2CH2C(CH3)2CH2NH2 (D) (CH3)2NCH2N(CH3)2

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