Question

The gravitational force of attraction between two masses depends on the distance between there is G = gravitational constant = \[K \times {10^{ - 11}}N{m^2}K{g^{ - 2}}\]. What is the value of K?

Answer 1

Hint: To solve this question use the value of gravitational constant G that is \[6.673 \times {10^{ - 11}}N{m^2}Kg\] and then refer to the format of the value of G given (i.e \[K \times {10^{ - 11}}N{m^2}K{g^{ - 2}}\]) and put the value of G before it and then match for the value of K.

Complete step by step answer:
As we know that the gravitational force is a force that attracts any two objects with mass. We call the gravitational force attractive because it always tries to pull masses together, it never pushes them apart. In fact, every object, including you, is pulling on every other object in the entire universe and Newton's law of universal gravitation is usually stated as that every particle attracts every other particle in the universe with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.
From Newton's universal law of gravitation the force is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centres of mass.
i.e., \[F = G\dfrac{{{m_1} \times {m_2}}}{{{r^2}}}\]
F = gravitational force.
\[{m_1},\,{m_2}\] = masses of two bodies
R = distance.
G = gravitational constant = \[6.673 \times {10^{ - 11}}N{m^2}Kg\]

Therefore value of K = 6.673

Note: In this type of question, we can infer that the force in gravitational force between two masses is inversely proportional to the square of the distance between them that is \[F = G\dfrac{{{m_1} \times {m_2}}}{{{r^2}}}\]
F = gravitational force.
\[{m_1},\,{m_2}\] = masses of two bodies
R = distance.