The gravitational field in a region is given by the equation $\vec { E } =\left( 5\hat { i } +12\hat { j } \right)$ N/kg. If the particle of mass 2kg is moved from the origin to the point (12m, 5m) in this region, the change in gravitational potential energy is
A. -225J
B. -240J
C. -245J
D. -250J
Answer
649.5k+ views
Hint: Gravitational potential energy is the energy that an object has due to its position or place in the gravitational force area. To find the difference in potential energy, we should use general expression derived from the gravitational law.
Formula used: ${ E }_{ x }=-\dfrac { dv }{ dr }$
Complete step by step answer:
The given equation of gravitational field is
$\vec { E } =\left( 5\hat { i } +12\hat { j } \right)$ It means that the potential is in two directions: x and y
First, let us find the potential in x – direction:
We know, ${ E }_{ x }=-\dfrac { dv }{ dr }$
It can also be written as, dv = -E.dr
On integrating both sides,
$\int { dv } =-\int { { E }_{ x } } dx$
Substituting the value of ${ E }_{ x }=5$
$\int { dv } =-\int { 5 } dx$
${ V }_{ x }=-5x$, now substitute x = 12 in the equation
${ V }_{ x }=-60V$.
Now, finding the potential in y – direction:
As seen before, ${ E }_{ y }=-\dfrac { dv }{ dr }$
It can also be written as, dv = -E.dr
On integrating both sides,
$\int{dv}=-{{E}_{y}}dy$
Substituting the value of ${ E }_{ y }=12$
$\int{dv}=-\int{12}dy$
${{V}_{y}}=-12y$, now substitute y = 5 in the equation
${ V }_{ y }=-60V$.
The total potential energy is given by ${ V }={ V }_{ x }+{ V }_{ y }$
V = -60-60 = -120V
The change in gravitational potential energy, work done = $ m\times \Delta V$
The given mass of the particle, m = 2kg
So, work done = 2 × -120 = -240 J
Therefore, the correct answer for the given question is option (B).
Note: Gravitational potential energy is often used for the objects that are on the earth’s surface as it can easily be considered as 9.8m/s2. The potential energy above a particular height is equal to the work done to raise the object to that height without losing any form of kinetic energy.
Formula used: ${ E }_{ x }=-\dfrac { dv }{ dr }$
Complete step by step answer:
The given equation of gravitational field is
$\vec { E } =\left( 5\hat { i } +12\hat { j } \right)$ It means that the potential is in two directions: x and y
First, let us find the potential in x – direction:
We know, ${ E }_{ x }=-\dfrac { dv }{ dr }$
It can also be written as, dv = -E.dr
On integrating both sides,
$\int { dv } =-\int { { E }_{ x } } dx$
Substituting the value of ${ E }_{ x }=5$
$\int { dv } =-\int { 5 } dx$
${ V }_{ x }=-5x$, now substitute x = 12 in the equation
${ V }_{ x }=-60V$.
Now, finding the potential in y – direction:
As seen before, ${ E }_{ y }=-\dfrac { dv }{ dr }$
It can also be written as, dv = -E.dr
On integrating both sides,
$\int{dv}=-{{E}_{y}}dy$
Substituting the value of ${ E }_{ y }=12$
$\int{dv}=-\int{12}dy$
${{V}_{y}}=-12y$, now substitute y = 5 in the equation
${ V }_{ y }=-60V$.
The total potential energy is given by ${ V }={ V }_{ x }+{ V }_{ y }$
V = -60-60 = -120V
The change in gravitational potential energy, work done = $ m\times \Delta V$
The given mass of the particle, m = 2kg
So, work done = 2 × -120 = -240 J
Therefore, the correct answer for the given question is option (B).
Note: Gravitational potential energy is often used for the objects that are on the earth’s surface as it can easily be considered as 9.8m/s2. The potential energy above a particular height is equal to the work done to raise the object to that height without losing any form of kinetic energy.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Trending doubts
Difference Between Prokaryotic Cells and Eukaryotic Cells

Two of the body parts which do not appear in MRI are class 11 biology CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

10 examples of friction in our daily life

Draw a diagram of nephron and explain its structur class 11 biology CBSE

What will happen if the mucus is not secreted by the class 11 biology CBSE

