Question

The gravitational field in a region is given by the equation $\overrightarrow{E}=(5\hat{i}+12\hat{j})$ N/kg. If the particle of mass 2kg is moved from the origin to the point (12m, 5m) in this region, the change in gravitational potential energy is
A. -225J
B. -240J
C. -245J
D. -250J

Answer 1

Hint: Gravitational potential energy is the energy that an object has due to its position or place in the gravitational force area. To find the difference in potential energy, we should use general expression derived from the gravitational law.
Formula used: $E_x=-{\displaystyle \frac{dv}{dr}}$

Complete step by step answer:
The given equation of gravitational field is
$\overrightarrow{E}=(5\hat{i}+12\hat{j})$ It means that the potential is in two directions: x and y
First, let us find the potential in x – direction:
We know, $E_x=-{\displaystyle \frac{dv}{dr}}$
It can also be written as, dv = -E.dr
On integrating both sides,
$\int dv=-\int E_{x}dx$
Substituting the value of $E_x=5$
$\int dv=-\int 5dx$
$V_x=-5x$, now substitute x = 12 in the equation
$V_x=-60V$.
Now, finding the potential in y – direction:
As seen before, $E_y=-{\displaystyle \frac{dv}{dr}}$
It can also be written as, dv = -E.dr
On integrating both sides,
$\int dv=-E_{y}dy$
Substituting the value of $E_y=12$
$\int dv=-\int 12dy$
$V_y=-12y$, now substitute y = 5 in the equation
$V_y=-60V$.
The total potential energy is given by $V=V_x+V_y$
V = -60-60 = -120V
The change in gravitational potential energy, work done = $m\times \mathrm{\Delta }V$
The given mass of the particle, m = 2kg
So, work done = 2 × -120 = -240 J
Therefore, the correct answer for the given question is option (B).

Note: Gravitational potential energy is often used for the objects that are on the earth’s surface as it can easily be considered as 9.8m/s2. The potential energy above a particular height is equal to the work done to raise the object to that height without losing any form of kinetic energy.