
The graph of \[2x + y = 3\] passes through the origin. Is this statement true or false?
A.True
B.False
Answer
594k+ views
Hint: As it is given that graph of the given equation passes through the origin, we insert the values of (x,y) i.e. \[(0,0)\], and check whether the equation satisfies, if yes then the statement is true, else it is false.
Complete step-by-step answer:
Given equation \[2x + y = 3\]
Here, we know that if the equation satisfies the point \[(0,0)\] then we say that the line passes through the origin.
For this, we put the value (0,0) in the given equation, we get
LHS=
\[(2 \times 0) + 0 = 0\]
As we see that LHS\[ \ne \]RHS.
Hence, the given line \[2x + y = 3\] does not pass through the origin.
Hence, the statement is false.
Hence, the correct option is (B)
Note: To check whether a point lies on the given line, we should always substitute the value of x coordinate in the place of x and the value of y coordinate in the place of y, if LHS is equal to RHS, then the point lies on the line.
Complete step-by-step answer:
Given equation \[2x + y = 3\]
Here, we know that if the equation satisfies the point \[(0,0)\] then we say that the line passes through the origin.
For this, we put the value (0,0) in the given equation, we get
LHS=
\[(2 \times 0) + 0 = 0\]
As we see that LHS\[ \ne \]RHS.
Hence, the given line \[2x + y = 3\] does not pass through the origin.
Hence, the statement is false.
Hence, the correct option is (B)
Note: To check whether a point lies on the given line, we should always substitute the value of x coordinate in the place of x and the value of y coordinate in the place of y, if LHS is equal to RHS, then the point lies on the line.
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