
The graph between the square root of the frequency of a specific line of characteristic spectrum of X-ray and the atomic number of the target will be
a)
b)
c)
d)
Answer
570.3k+ views
Hint:It has been observed that the frequency of the characteristic spectrum of X-ray and the atomic number of the target is dependent in such a way that the frequency is proportional to the square of the atomic number with an offset value.
Formula used:
Relationship between the frequency of characteristic spectrum of X-ray and the atomic number is given by:
$\nu = a{(Z - b)^2}$...................(1)
Where,
$\nu $ is the frequency of characteristic spectrum of X-ray,
Z denotes the atomic number of the target atom,
a is the proportionality constant and a is positive,
b is offset constant and it’s positive also.
Complete step by step answer:
From eq.(1) we get the relationship between$\sqrt \nu $and Z as:
$
\nu = a{(Z - b)^2} \\
\therefore \sqrt \nu = \sqrt a Z - \sqrt a b \\
$.............................(2)
Now, compare this eq.(2) with the equation of a straight line i.e. $y = mx + c$. You will see that$\sqrt \nu $and Z are linearly related to each other with slope$\sqrt a $with an intercept $ - \sqrt a b$. So, the line will cut x-axis at +b point. Hence, the graph of $\sqrt \nu $ vs Z will look like:
Where, square roots of frequency values are given at y axis and the atomic number Z is given in the x-axis.
Correct answer:
The correct graph is given in option (b).
Note: From the given relation between frequency of characteristic spectrum and atomic number in eq.(1) a student can easily determine that the relationship between$\sqrt \nu $and Z will be linear. But they might get confused when choosing one between the first 3 straight line options. So, you need to focus on eq.(2). You will see that the line must have a negative intercept with y-axis. But in option a and option c the intercepts are positive and zero respectively. So, you’ll get the correct answer as graph b.
Formula used:
Relationship between the frequency of characteristic spectrum of X-ray and the atomic number is given by:
$\nu = a{(Z - b)^2}$...................(1)
Where,
$\nu $ is the frequency of characteristic spectrum of X-ray,
Z denotes the atomic number of the target atom,
a is the proportionality constant and a is positive,
b is offset constant and it’s positive also.
Complete step by step answer:
From eq.(1) we get the relationship between$\sqrt \nu $and Z as:
$
\nu = a{(Z - b)^2} \\
\therefore \sqrt \nu = \sqrt a Z - \sqrt a b \\
$.............................(2)
Now, compare this eq.(2) with the equation of a straight line i.e. $y = mx + c$. You will see that$\sqrt \nu $and Z are linearly related to each other with slope$\sqrt a $with an intercept $ - \sqrt a b$. So, the line will cut x-axis at +b point. Hence, the graph of $\sqrt \nu $ vs Z will look like:
Where, square roots of frequency values are given at y axis and the atomic number Z is given in the x-axis.
Correct answer:
The correct graph is given in option (b).
Note: From the given relation between frequency of characteristic spectrum and atomic number in eq.(1) a student can easily determine that the relationship between$\sqrt \nu $and Z will be linear. But they might get confused when choosing one between the first 3 straight line options. So, you need to focus on eq.(2). You will see that the line must have a negative intercept with y-axis. But in option a and option c the intercepts are positive and zero respectively. So, you’ll get the correct answer as graph b.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

Which animal has three hearts class 11 biology CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

