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# The frequency of the visible light of wavelength 6000 A$^o$ (Angstrom unit) is\begin{align} & \text{A}\text{. }4\times {{10}^{14}}Hz \\ & \text{B}\text{. }6000 \\ & \text{C}\text{. }5\times {{10}^{10}}Hz \\ & \text{D}\text{. }5\times {{10}^{14}}Hz \\ \end{align}

Last updated date: 12th Aug 2024
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Hint: Frequency is the number of repeated events occurring per unit time. In terms of wavelength frequency is given as speed of light upon wavelength of light. By using this formula we can find the frequency of the visible light as wavelength is given and speed of light is a universal constant which we know.

Formula used:
$f=\dfrac{c}{\lambda }$

The frequency is the number of waves passing at a particular interval of time. The frequency for the electromagnetic wave is given as
$f=\dfrac{c}{\lambda }$
The visible light lies in the electromagnetic spectra between the infrared region and the ultra-violet region and which is visible to the human eye and therefore it is named as visible light or visible region. Hence, we can calculate the frequency of the visible light by the above formula where c is the speed of light and its value is $c=3\times {{10}^{8}}m/s$

Substituting the value of λ
\begin{align} & \lambda =6000 A^o \\ & \lambda =6000\times {{10}^{-10}}m \\ \end{align}

Then the frequency is given as
\begin{align} & f=\dfrac{3\times {{10}^{8}}}{6000\times {{10}^{-10}}}Hz \\ & f=0.0005\times {{10}^{18}}Hz \\ & f=5\times {{10}^{14}}Hz \\ \end{align}

So, the correct answer is “Option D”.