
The frequency of a fork is $200\;{\rm{Hz}}$. The distance through which sound travels by the time the fork make $16$ vibrations is (velocity of sound in air is $340\;{{\rm{m}} {\left/
{\vphantom {{\rm{m}} {\rm{s}}}} \right.
} {\rm{s}}}$):
a). ${\rm{34}}\;{\rm{m}}$
b). $21.25\;{\rm{m}}$
c). $425\;{\rm{m}}$
(D). ${\rm{27}}{\rm{.2}}\;{\rm{m}}$
Answer
482.4k+ views
Hint: We know that the total Distance covered in one time period or in one vibration is known as wavelength. So, we first calculate the wavelength for first vibration then multiply it by $16$ to find the total distance covered in $16$ vibrations.
Complete step by step answer:Given:
The velocity of sound in air is $v = 340\;{{\rm{m}} {\left/
{\vphantom {{\rm{m}} {\rm{s}}}} \right.
} {\rm{s}}}$.
The frequency of a fork is $f = 200\;{\rm{Hz}}$.
The vibration or oscillation is a type of motion that reoccurs in a regular interval of time. The swinging of a pendulum and the tines of a tuning fork are the examples of vibrations.
The study of oscillatory motions of any body and the forces acting on them are studied under the theory of vibrations.
In the other words, the wavelength is the measure of length between two similar crest of a waveform created by the propagation of wave along a wire or in space. The unit of wavelength can be meters.
The formula to calculate the wavelength is given by,
$\lambda = \dfrac{v}{f}$
Here, $v$ is the velocity of the sound in air, $f$ is the frequency of a fork, and $\lambda $ is the wavelength.
Substituting the values of $v$and $f$ in the equation $\lambda = \dfrac{v}{f}$, we get,
$\begin{array}{c}
\lambda = \dfrac{{340}}{{200}}\\
= 1.7\;{\rm{m}}
\end{array}$
Find the distance covered in $16$ vibrations as follows.
$s = 16\lambda $
Substituting the value of $\lambda $ in the equation $s = 16\lambda $, we get,
$\begin{array}{c}
s = 16\left( {1.7\;{\rm{m}}} \right)\\
= 27.2\;{\rm{m}}
\end{array}$
Hence, the option (D) is the correct answer.
Note:We can use an alternate method to solve this problem. First calculate the time period by using formula ${\rm{Time}}\;{\rm{period}} = \dfrac{1}{{{\rm{Frequency}}\left( f \right)}}$, then calculate the total time by using formula ${\rm{Total}}\;{\rm{time}} = {\rm{Time}}\;{\rm{period}} \times {\rm{number}}\;{\rm{of}}\;{\rm{vibrations}}$, and finally required distance is calculated by using formula ${\rm{Distance}}\;{\rm{travelled}} = {\rm{Speed}} \times {\rm{Total}}\;{\rm{time}}$.
Complete step by step answer:Given:
The velocity of sound in air is $v = 340\;{{\rm{m}} {\left/
{\vphantom {{\rm{m}} {\rm{s}}}} \right.
} {\rm{s}}}$.
The frequency of a fork is $f = 200\;{\rm{Hz}}$.
The vibration or oscillation is a type of motion that reoccurs in a regular interval of time. The swinging of a pendulum and the tines of a tuning fork are the examples of vibrations.
The study of oscillatory motions of any body and the forces acting on them are studied under the theory of vibrations.
In the other words, the wavelength is the measure of length between two similar crest of a waveform created by the propagation of wave along a wire or in space. The unit of wavelength can be meters.
The formula to calculate the wavelength is given by,
$\lambda = \dfrac{v}{f}$
Here, $v$ is the velocity of the sound in air, $f$ is the frequency of a fork, and $\lambda $ is the wavelength.
Substituting the values of $v$and $f$ in the equation $\lambda = \dfrac{v}{f}$, we get,
$\begin{array}{c}
\lambda = \dfrac{{340}}{{200}}\\
= 1.7\;{\rm{m}}
\end{array}$
Find the distance covered in $16$ vibrations as follows.
$s = 16\lambda $
Substituting the value of $\lambda $ in the equation $s = 16\lambda $, we get,
$\begin{array}{c}
s = 16\left( {1.7\;{\rm{m}}} \right)\\
= 27.2\;{\rm{m}}
\end{array}$
Hence, the option (D) is the correct answer.
Note:We can use an alternate method to solve this problem. First calculate the time period by using formula ${\rm{Time}}\;{\rm{period}} = \dfrac{1}{{{\rm{Frequency}}\left( f \right)}}$, then calculate the total time by using formula ${\rm{Total}}\;{\rm{time}} = {\rm{Time}}\;{\rm{period}} \times {\rm{number}}\;{\rm{of}}\;{\rm{vibrations}}$, and finally required distance is calculated by using formula ${\rm{Distance}}\;{\rm{travelled}} = {\rm{Speed}} \times {\rm{Total}}\;{\rm{time}}$.
Recently Updated Pages
The correct geometry and hybridization for XeF4 are class 11 chemistry CBSE

Water softening by Clarks process uses ACalcium bicarbonate class 11 chemistry CBSE

With reference to graphite and diamond which of the class 11 chemistry CBSE

A certain household has consumed 250 units of energy class 11 physics CBSE

The lightest metal known is A beryllium B lithium C class 11 chemistry CBSE

What is the formula mass of the iodine molecule class 11 chemistry CBSE

Trending doubts
Is Cellular respiration an Oxidation or Reduction class 11 chemistry CBSE

In electron dot structure the valence shell electrons class 11 chemistry CBSE

What is the Pitti Island famous for ABird Sanctuary class 11 social science CBSE

State the laws of reflection of light

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells
