Question

The fragrance compounds of perfumes are often dissolved in solvent Y, which has a molecular formula \[{C_7}{H_{12}}{O_4}\]. It is made by reacting propane -1,2-diol with ethanoic acid in the presence of a catalyst.
What is the structure of solvent Y

 Propane-1,2-diol
A.

B.

C.

D.

Answer 1

Hint: We must have to know that the diol group contains two hydroxyl functional groups which are attached to the same carbon atom. The menthanez diol is the simplest diol. Propane -1,2-diol contains two hydroxyl groups. Here, the propane -1,2-diol is reacted with ethanoic acid. The ethanoic acid is also known as acetic acid and has the chemical formula, \[C{H_3}COOH\].

Complete answer:
This is not the correct structure of solvent Y. Hence, option (A) is incorrect.
When propane -1,2-diol reacts with ethanoic acid, there is a formation of an ester compound which contains two ester groups. Hence, the option (B) is incorrect.
Here, the diol is reacted with ethanoic acid. Therefore, the product should be an ester. But this is not the correct structure of solvent Y. Hence, option (C) is incorrect.
The fragrance compounds of perfumes are often dissolved in solvent Y and the molecular formula of the solvent is \[{C_7}{H_{12}}{O_4}\]. And it can be prepared by the reaction of propane -1,2-diol and ethanoic acid. There is a formation of ester and that is, 2-(formyloxy)propyl acetate. Let’s see the chemical reaction of propane -1,2-diol with ethanoic acid,

Hence, the option (D) is correct.

Note:
As we know that when the diol is reacting with an acid, there is a formation of ester. The diol contains two hydroxyl groups as functional groups. And this is reacted with the ethanoic acid. Hence, there is a formation of ester, which is 2-(formyloxy) propyl acetate. And it contains two ester groups. But the remaining three structures contain only one ester group and it’s not a correct structure of the given solvent.