Question

The formation of $A{r_2}$ is possible.
Enter $1$ if the statement is true is TRUE and enter $0$ if the statement is FALSE.

Answer 1

Hint:We know that a molecule is formed when an atom has to gain stability. So we will use the properties of noble gases to verify whether the statement is true or false. The electronic configuration is \[1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}\]. Thus, a filled orbital is present for Argon.

Complete step by step answer:
-We know that an atom acquires stability by forming molecules.
-Also in the case of argon, it is a noble gas and we know that noble gases are themselves stable as they complete their octet which means they have eight electrons in their valence shell.
-So in the case of argon due to the noble gas, it is pretty much stable and does not need to form a molecule for gaining stability as it is already stable.
-Also, a molecule is formed to gain stability and achieve a noble gas configuration.
These noble gas have zero valence electrons and have achieved exceptional stability therefore they cannot pair up with another atom of its own and form a molecule.
-Therefore argon cannot form $A{r_2}$ a molecule.

Therefore, the answer is zero as the statement is false.


Note:
The octet rule for the stability of compounds and the number of valence electrons needed for the stability and for achieving noble gas configuration. Argon does not form many compounds due to the inertness it got being a noble gas. All the noble gases are monatomic molecules. The valency of the atom is 1. Argon- 36 in the form of Argon hydride ions have been detected in the interstellar medium.