The following table shows the marks obtained by 200 students at an examination in mathematics. Find the mean of the data.
Marks 0- 10 10-20 20-30 30-40 40-50 50-60 60-70 70-80 80-90 90-100 Number of students 05 10 11 20 27 38 40 29 14 06
| Marks | 0- 10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 | 80-90 | 90-100 |
| Number of students | 05 | 10 | 11 | 20 | 27 | 38 | 40 | 29 | 14 | 06 |
Answer
603.9k+ views
Hint:For solving this problem we create a table of some columns that contain number of students as \[{{f}_{i}}\], midpoint of marks given as \[{{x}_{i}}\], product of number of students and midpoint of marks as \[{{f}_{i}}{{x}_{i}}\], then we calculate the value of mean using the formula \[\bar{x}=\dfrac{\sum{{{f}_{i}}{{x}_{i}}}}{\sum{{{f}_{i}}}}\].
Complete step-by-step solution
Let us assume that the given number of students in each interval is represented as \[{{f}_{i}}\].
Now let us create the table that contain number of students as \[{{f}_{i}}\], midpoint of marks given as \[{{x}_{i}}\], product of number of students and midpoint of marks as \[{{f}_{i}}{{x}_{i}}\].
Now, we know that the mean of the continuous data can be calculated by using the formula
\[\bar{x}=\dfrac{\sum{{{f}_{i}}{{x}_{i}}}}{\sum{{{f}_{i}}}}...........equation(i)\]
Let us find the unknown values.
\[\sum{{{f}_{i}}}\] is calculated by adding all the students, which in turn gives the total number of students.
In the question, we are given that the total number of students is 200.
Therefore, we can write \[\sum{{{f}_{i}}}=200\].
Now let us find the value of \[\sum{{{f}_{i}}{{x}_{i}}}\].
By adding all the values in the column \[{{f}_{i}}{{x}_{i}}\] we get
\[\begin{align}
& \Rightarrow \sum{{{f}_{i}}{{x}_{i}}}=25+150+275+700+1215+2090+2600+2175+1190+570 \\
& \Rightarrow \sum{{{f}_{i}}{{x}_{i}}}=10990 \\
\end{align}\]
Now by substituting the values of \[\sum{{{f}_{i}}}\] and \[\sum{{{f}_{i}}{{x}_{i}}}\] in equation (i) we get
\[\begin{align}
& \Rightarrow \bar{x}=\dfrac{\sum{{{f}_{i}}{{x}_{i}}}}{\sum{{{f}_{i}}}} \\
& \Rightarrow \bar{x}=\dfrac{10990}{200} \\
& \Rightarrow \bar{x}=54.95 \\
\end{align}\]
Therefore the mean of given data is 54.95.
Note: Students may make mistakes in calculating the value of \[{{f}_{i}}{{x}_{i}}\]. As the data is written in one line type students may do multiplication mistake instead of multiplying the corresponding \[{{f}_{i}}\] and \[{{x}_{i}}\] values, in a hurry they multiply the value of \[{{x}_{i}}\] and different value of \[{{f}_{i}}\] which results in the wrong answer. The calculation part only needs to be taken care of.
Complete step-by-step solution
Let us assume that the given number of students in each interval is represented as \[{{f}_{i}}\].
Now let us create the table that contain number of students as \[{{f}_{i}}\], midpoint of marks given as \[{{x}_{i}}\], product of number of students and midpoint of marks as \[{{f}_{i}}{{x}_{i}}\].
| Marks | Number of students\[{{f}_{i}}\] | Midpoint of marks\[{{x}_{i}}\] | \[{{f}_{i}}{{x}_{i}}\] |
| 0-10 | 05 | 5 | 25 |
| 10-20 | 10 | 15 | 150 |
| 20-30 | 11 | 25 | 275 |
| 30-40 | 20 | 35 | 700 |
| 40-50 | 27 | 45 | 1215 |
| 50-60 | 38 | 55 | 2090 |
| 60-70 | 40 | 65 | 2600 |
| 70-80 | 29 | 75 | 2175 |
| 80-90 | 14 | 85 | 1190 |
| 90-100 | 06 | 95 | 570 |
Now, we know that the mean of the continuous data can be calculated by using the formula
\[\bar{x}=\dfrac{\sum{{{f}_{i}}{{x}_{i}}}}{\sum{{{f}_{i}}}}...........equation(i)\]
Let us find the unknown values.
\[\sum{{{f}_{i}}}\] is calculated by adding all the students, which in turn gives the total number of students.
In the question, we are given that the total number of students is 200.
Therefore, we can write \[\sum{{{f}_{i}}}=200\].
Now let us find the value of \[\sum{{{f}_{i}}{{x}_{i}}}\].
By adding all the values in the column \[{{f}_{i}}{{x}_{i}}\] we get
\[\begin{align}
& \Rightarrow \sum{{{f}_{i}}{{x}_{i}}}=25+150+275+700+1215+2090+2600+2175+1190+570 \\
& \Rightarrow \sum{{{f}_{i}}{{x}_{i}}}=10990 \\
\end{align}\]
Now by substituting the values of \[\sum{{{f}_{i}}}\] and \[\sum{{{f}_{i}}{{x}_{i}}}\] in equation (i) we get
\[\begin{align}
& \Rightarrow \bar{x}=\dfrac{\sum{{{f}_{i}}{{x}_{i}}}}{\sum{{{f}_{i}}}} \\
& \Rightarrow \bar{x}=\dfrac{10990}{200} \\
& \Rightarrow \bar{x}=54.95 \\
\end{align}\]
Therefore the mean of given data is 54.95.
Note: Students may make mistakes in calculating the value of \[{{f}_{i}}{{x}_{i}}\]. As the data is written in one line type students may do multiplication mistake instead of multiplying the corresponding \[{{f}_{i}}\] and \[{{x}_{i}}\] values, in a hurry they multiply the value of \[{{x}_{i}}\] and different value of \[{{f}_{i}}\] which results in the wrong answer. The calculation part only needs to be taken care of.
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