Answer
Verified
457.2k+ views
Hint: First find the angle occupied by each game and then draw the graph.
Here, ${\theta _C},{\theta _F},{\theta _H},{\theta _B}$ are the angles occupied by Cricket, Football, Hockey and Basketball respectively.
$\theta $ is the angle, which is used to draw the graph.
Complete step-by-step answer:
To find the $\theta $ we can use this formula.
$\theta = \dfrac{{{\text{Given}}\;{\text{Quantity}}}}{{{\text{Total}}\;{\text{Quantity}}}} \times 360^\circ $
Here, the given quantity is the number of students playing each game.
Total quantity is the total no of students and $360^\circ $ is the total angle of a circle.
According to the question:
Total no of students = 40.
No. of students who play Cricket = 20.
No. of students who play Football = 10.
No. of students who play Hockey = 5
No. of students who play Basketball = 5
Now, we need to find the angle subtended by each game on the circle.
$\therefore $ angle subtended by cricket = ${\theta _c}$
${\theta _c} = \dfrac{{{2}{0}}}{{{4}{0}}} \times 360^\circ = 180$
$\therefore $ angle subtended by football = $\theta r$
${\theta _F} = \dfrac{{1{0}}}{{4{0}}} \times 360^\circ = 90^\circ $
$\therefore $ angle subtended by Hockey = \[{\theta _H}\]
\[{\theta _H} = \dfrac{5}{{{4}{0}}} \times \mathop {{3}{6}0} = 45^\circ \]
$\therefore $ angle subtended by Basketball = ${\theta _B}$
\[{\theta _B} = \dfrac{5}{{{4}{0}}} \times \mathop {{3}{6}0}= 45^\circ \]
So now, we have all the data required to draw a circle graph.
$\therefore $ the graph will be like
${\theta _C}$ = Cricket
${\theta _F}$ = Football
${\theta _H}$ = Hockey
${\theta _B}$ = Basketball
Note: In the question where the graph is required to draw.
We will 1st process the data. Also we could have made this by finding the percentage covered by each game.
Like the area covered by cricket = Ac.
Ac \[ = \dfrac{{{2}{0}}}{{4{0}}} \times \mathop {1{0}{0}} = 50\% \] area.
Similarly
AF = $\dfrac{{1{0}}}{{4{0}}} \times 100 = 25\% $ area.
AH = $\dfrac{5}{{\mathop {{4}{0}}\limits_2 }} \times \mathop {{1}{0}{0}} = \dfrac{{25}}{2} = 12.5\% $. area
AB = $\dfrac{5}{{40}} \times 100 = 12.5\% $ area
Here, ${\theta _C},{\theta _F},{\theta _H},{\theta _B}$ are the angles occupied by Cricket, Football, Hockey and Basketball respectively.
$\theta $ is the angle, which is used to draw the graph.
Complete step-by-step answer:
To find the $\theta $ we can use this formula.
$\theta = \dfrac{{{\text{Given}}\;{\text{Quantity}}}}{{{\text{Total}}\;{\text{Quantity}}}} \times 360^\circ $
Here, the given quantity is the number of students playing each game.
Total quantity is the total no of students and $360^\circ $ is the total angle of a circle.
According to the question:
Total no of students = 40.
No. of students who play Cricket = 20.
No. of students who play Football = 10.
No. of students who play Hockey = 5
No. of students who play Basketball = 5
Now, we need to find the angle subtended by each game on the circle.
$\therefore $ angle subtended by cricket = ${\theta _c}$
${\theta _c} = \dfrac{{{2}{0}}}{{{4}{0}}} \times 360^\circ = 180$
$\therefore $ angle subtended by football = $\theta r$
${\theta _F} = \dfrac{{1{0}}}{{4{0}}} \times 360^\circ = 90^\circ $
$\therefore $ angle subtended by Hockey = \[{\theta _H}\]
\[{\theta _H} = \dfrac{5}{{{4}{0}}} \times \mathop {{3}{6}0} = 45^\circ \]
$\therefore $ angle subtended by Basketball = ${\theta _B}$
\[{\theta _B} = \dfrac{5}{{{4}{0}}} \times \mathop {{3}{6}0}= 45^\circ \]
So now, we have all the data required to draw a circle graph.
$\therefore $ the graph will be like
${\theta _C}$ = Cricket
${\theta _F}$ = Football
${\theta _H}$ = Hockey
${\theta _B}$ = Basketball
Note: In the question where the graph is required to draw.
We will 1st process the data. Also we could have made this by finding the percentage covered by each game.
Like the area covered by cricket = Ac.
Ac \[ = \dfrac{{{2}{0}}}{{4{0}}} \times \mathop {1{0}{0}} = 50\% \] area.
Similarly
AF = $\dfrac{{1{0}}}{{4{0}}} \times 100 = 25\% $ area.
AH = $\dfrac{5}{{\mathop {{4}{0}}\limits_2 }} \times \mathop {{1}{0}{0}} = \dfrac{{25}}{2} = 12.5\% $. area
AB = $\dfrac{5}{{40}} \times 100 = 12.5\% $ area
Recently Updated Pages
Who among the following was the religious guru of class 7 social science CBSE
what is the correct chronological order of the following class 10 social science CBSE
Which of the following was not the actual cause for class 10 social science CBSE
Which of the following statements is not correct A class 10 social science CBSE
Which of the following leaders was not present in the class 10 social science CBSE
Garampani Sanctuary is located at A Diphu Assam B Gangtok class 10 social science CBSE
Trending doubts
Derive an expression for drift velocity of free electrons class 12 physics CBSE
Which are the Top 10 Largest Countries of the World?
Write down 5 differences between Ntype and Ptype s class 11 physics CBSE
The energy of a charged conductor is given by the expression class 12 physics CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Derive an expression for electric field intensity due class 12 physics CBSE
How do you graph the function fx 4x class 9 maths CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Derive an expression for electric potential at point class 12 physics CBSE