The expression for electric field intensity at a point which is outside a uniformly charged thin plane sheet is (d is the distance of point from plane sheet)
A. independent of $d$ $C{{m}^{-2}}$
B. directly proportional to $\sqrt{d}$
C. directly proportional to $d$
D. directly proportional to $\dfrac{1}{\sqrt{d}}$
Answer
624.6k+ views
Hint: Here we have to draw a cylindrical Gaussian surface.
The electric field intensity at a point is given by the formula,
$E=\dfrac{\sigma }{{{\varepsilon }_{0}}}$
Where $E$ be the electric field vector, $\sigma $ is the electric charge density of the plane sheet and ${{\varepsilon }_{0}}$ is the specific inductive capacity or the relative permittivity of the thin plane sheet. And then find the relation between the terms.
Complete step-by-step answer:
First of all let us take a look at what actually the electric field intensity means. The electric field Intensity at a point is given as the force felt by a unit positive charge kept at a particular point. Electric Field Intensity is basically a vector quantity. It is denoted by $E$. It can be written in a formula like,
$E=\dfrac{F}{q}$
For an infinite sheet of charge, the electric field is found to be perpendicular to the surface. Because of this, only the ends of a cylindrical Gaussian surface will be contributing to the electric flux.
Here in this question, it is mentioned that the sheet is plane uniformly charged. Therefore the electric field is given by the equation,
$E=\dfrac{\sigma }{{{\varepsilon }_{0}}}$
By looking at this equation we are able to find that the electric field intensity is not having any sort of connection with the distance of the point from the plain sheet. Therefore the correct answer is option A.
So, the correct answer is “Option A”.
Note: Surface charge density denoted as $\sigma $, calculated in coulombs per square meter, $C{{m}^{-2}}$ is an amount of charge per unit area at any point on a surface charge distribution, in the case of a two dimensional surface. Since electric charge will be either positive or negative, charge density can be expressed as either positive or negative values.
The electric field intensity at a point is given by the formula,
$E=\dfrac{\sigma }{{{\varepsilon }_{0}}}$
Where $E$ be the electric field vector, $\sigma $ is the electric charge density of the plane sheet and ${{\varepsilon }_{0}}$ is the specific inductive capacity or the relative permittivity of the thin plane sheet. And then find the relation between the terms.
Complete step-by-step answer:
First of all let us take a look at what actually the electric field intensity means. The electric field Intensity at a point is given as the force felt by a unit positive charge kept at a particular point. Electric Field Intensity is basically a vector quantity. It is denoted by $E$. It can be written in a formula like,
$E=\dfrac{F}{q}$
For an infinite sheet of charge, the electric field is found to be perpendicular to the surface. Because of this, only the ends of a cylindrical Gaussian surface will be contributing to the electric flux.
Here in this question, it is mentioned that the sheet is plane uniformly charged. Therefore the electric field is given by the equation,
$E=\dfrac{\sigma }{{{\varepsilon }_{0}}}$
By looking at this equation we are able to find that the electric field intensity is not having any sort of connection with the distance of the point from the plain sheet. Therefore the correct answer is option A.
So, the correct answer is “Option A”.
Note: Surface charge density denoted as $\sigma $, calculated in coulombs per square meter, $C{{m}^{-2}}$ is an amount of charge per unit area at any point on a surface charge distribution, in the case of a two dimensional surface. Since electric charge will be either positive or negative, charge density can be expressed as either positive or negative values.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

Why is the cell called the structural and functional class 12 biology CBSE

When was the first election held in India a 194748 class 12 sst CBSE

Draw ray diagrams each showing i myopic eye and ii class 12 physics CBSE

