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# The elements having electronic configuration $\left( \text{Kr} \right)\text{4}{{\text{d}}^{\text{10}}}\text{,4}{{\text{f}}^{\text{14}}}\text{, 5}{{\text{s}}^{\text{2}}}\text{, 5}{{\text{p}}^{\text{6}}}\text{, 5}{{\text{d}}^{\text{2}}}\text{, 6}{{\text{s}}^{\text{2}}}$ belongs toA.s-blockB.p-blockC.d-blockD.d-block

Last updated date: 02nd Aug 2024
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Hint:Electronic configuration defined as arrangement of electrons of atom and molecule into the atomic orbital in increasing energy. There are four kinds of atomic orbital present i.e. s, p, d, F. According to atomic theory and quantum mechanics, an atomic orbital is a mathematical function describing the location and wave-like behavior of an electron in an atom. This function can be used to calculate the probability of finding any electron of an atom in any specific region around the atom's nucleus.

The given electronic configuration is $\left( \text{Kr} \right)\text{4}{{\text{d}}^{\text{10}}}\text{,4}{{\text{s}}^{\text{14}}}\text{, 5}{{\text{s}}^{\text{2}}}\text{, 5}{{\text{p}}^{\text{6}}}\text{, 5}{{\text{d}}^{\text{2}}}\text{, 6}{{\text{s}}^{\text{2}}}$
The last electron in this electronic configuration enters in S-orbital so that the element belongs to s-block.

Hence, Option [A] is correct i.e. s-block element.