
The electrolytic reduction process is used for the extraction of:
A.Highly electropositive metals
B.Metalloids
C.Less reactive metals
D.Transition metals
Answer
574.5k+ views
Hint: There are many methods that are used for extracting the metals from their ores which include reduction of metals, oxides with carbon reduction or electrolytic reduction of the molten metal chlorides, oxides and hydroxides. Methods used for a metal depend on its physical and chemical properties.
Complete step by step answer:
The type of extraction method to be used for the extraction of the metals from their ores depends upon its position in the reactivity series. Metals that lie below the carbon in the reactivity series can be extracted from their respective oxides by heating them with carbon. In this reaction, carbon gets oxidised to carbon dioxide while the metal oxide gets reduced to its respective metal.
But for the metals that lie above carbon in the reactivity series, their respective oxides cannot be reduced by heating it with carbon dioxide. For extracting these metals, electrolytic reduction of their respective molten chlorides, oxides or hydroxides is performed. Let us explain the electrolytic reduction method with the help of an example. Sodium is extracted by electrolytic reduction of molten sodium chloride. When the current is passed through fused sodium chloride, sodium ion is reduced at the cathode while chloride ions are oxidised at the anode. The chemical reactions are given below:
At anode (negatively charge), $2N{a^ + } + 2{e^ - } \to 2Na(s)$
At cathode (positive charge), $2C{l^ - } \to C{l_2}(g) + 2{e^ - }$
Thus, these metals are more electropositive than carbon. Then, the metals which are highly electropositive are extracted by electrolytic reduction.
Hence correct answer is option A.
Note:
In the reactivity series of metals, metals are arranged from the most reactive to the least reactive or decreasing reactivity. This series is based upon the reactivity of different metals and non-metals which has been made after carefully observing their reactions with water, acids and other metallic compounds.
Complete step by step answer:
The type of extraction method to be used for the extraction of the metals from their ores depends upon its position in the reactivity series. Metals that lie below the carbon in the reactivity series can be extracted from their respective oxides by heating them with carbon. In this reaction, carbon gets oxidised to carbon dioxide while the metal oxide gets reduced to its respective metal.
But for the metals that lie above carbon in the reactivity series, their respective oxides cannot be reduced by heating it with carbon dioxide. For extracting these metals, electrolytic reduction of their respective molten chlorides, oxides or hydroxides is performed. Let us explain the electrolytic reduction method with the help of an example. Sodium is extracted by electrolytic reduction of molten sodium chloride. When the current is passed through fused sodium chloride, sodium ion is reduced at the cathode while chloride ions are oxidised at the anode. The chemical reactions are given below:
At anode (negatively charge), $2N{a^ + } + 2{e^ - } \to 2Na(s)$
At cathode (positive charge), $2C{l^ - } \to C{l_2}(g) + 2{e^ - }$
Thus, these metals are more electropositive than carbon. Then, the metals which are highly electropositive are extracted by electrolytic reduction.
Hence correct answer is option A.
Note:
In the reactivity series of metals, metals are arranged from the most reactive to the least reactive or decreasing reactivity. This series is based upon the reactivity of different metals and non-metals which has been made after carefully observing their reactions with water, acids and other metallic compounds.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
Differentiate between an exothermic and an endothermic class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

