
The distance travelled by the particle in 8 sec is
A. 18m
B. 16m
C. 8m
D. 6m
Answer
584.4k+ views
Hint: At first look at the graph and analyze it, we will see that the car is first accelerating and then decelerating. So calculate the part at first where it is accelerating and then calculate the decelerating part to find the required result.
Complete answer:
The graph that is given is actually a time velocity graph from which we can define many things like distance travelled.
Now, to find the distance travelled by the particle in time t=8 seconds.
We can do that by, using the formula,
\[S=\dfrac{1}{2}\times (4+2)\times 4+\dfrac{1}{2}\times (2+4)\times 2\] , in this formula we are at fist covering the area or the distance where the graph is positive and then we calculated the distance where the graph is negative.
So on solving, we get
\[S=12+6=18m\]
So, the correct answer is “Option A”.
Additional Information:
Velocity of an object is the rate of change of the object’s position with respect to a frame of reference and which is always a function of time.
Accelerating is nothing but a measure of a body’s capacity of gaining velocity with respect to time or we can say that it is the rate of change of velocity with respect to time and it is a vector quantity
Note:
In the graph we can see that the body is accelerating at first and then slowly it starts to decelerate and then finally comes to a stop. We can find the acceleration of the body from the graph also we can also calculate the time taken to travel a distance from the graph
Complete answer:
The graph that is given is actually a time velocity graph from which we can define many things like distance travelled.
Now, to find the distance travelled by the particle in time t=8 seconds.
We can do that by, using the formula,
\[S=\dfrac{1}{2}\times (4+2)\times 4+\dfrac{1}{2}\times (2+4)\times 2\] , in this formula we are at fist covering the area or the distance where the graph is positive and then we calculated the distance where the graph is negative.
So on solving, we get
\[S=12+6=18m\]
So, the correct answer is “Option A”.
Additional Information:
Velocity of an object is the rate of change of the object’s position with respect to a frame of reference and which is always a function of time.
Accelerating is nothing but a measure of a body’s capacity of gaining velocity with respect to time or we can say that it is the rate of change of velocity with respect to time and it is a vector quantity
Note:
In the graph we can see that the body is accelerating at first and then slowly it starts to decelerate and then finally comes to a stop. We can find the acceleration of the body from the graph also we can also calculate the time taken to travel a distance from the graph
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

