Question

The distance at which Nilesh can throw a javelin is inversely proportional to the weight of the javelin. Nilesh can throw a 1.5-pound javelin exactly 260 feet. How far would Nilesh be able to throw a two-pound javelin, in feet, assuming all other factors remain constant? (Disregard units when inputting your answer.)
A) 195
B) 205
C) 207
D) 211

Answer 1

Hint:
In this question, it is given that distance is inversely proportional to the weight of the javelin. It means if the weight of the javelin is less then it will cover more distance because they are inversely proportional. If Nilesh throws 1.5-pound of javelin then it covers a distance of 260 feet. If he throws a javelin of 2 pound then it must cover a distance which is less than 260 feet because distance is inversely proportional to the weight of the javelin.

Complete step by step solution:
As it is given that Nilesh can throw javelin which is inversely proportional to the weight of javelin and we have to calculate how far Nilesh will be able to throw a 2 pound javelin.
Firstly, he throws a javelin of 1.5 pound which is up to 260 feet.
Then he throws javelin of weight 2 pound up to = \[\dfrac{{260 \times 1.5}}{2}\] feet
On simplifying it further we get,
\[ \Rightarrow \dfrac{{390}}{2}\] feet
On dividing 390 with 2 we get,
\[ \Rightarrow 195\] feet
As we have to ignore the units according to the question so the answer is equals to 195.

Option (A) 195 is the correct option.

Note:
To solve these types of questions, we need to remember that it is inversely proportional when one value decreases at the same rate that the other increases. We must read the given statement carefully and convert them in the form of equations and solve it further.