
The dimensions of latent heat are –
$A)\text{ }{{M}^{0}}{{L}^{2}}{{T}^{-2}}$
$B)\text{ }{{M}^{0}}{{L}^{1}}{{T}^{-2}}$
$C)\text{ }{{M}^{2}}{{L}^{0}}{{T}^{-2}}$
$D)\text{ }{{M}^{0}}{{L}^{-2}}{{T}^{-2}}$
Answer
581.1k+ views
Hint: This problem can be solved by using the definition of latent heat in terms of the heat involved in the phase change of a body and its mass. By writing the dimensions of the physical quantities in the mathematical definition for latent heat, we can get the required dimensions for latent heat.
Formula used:
$L=\dfrac{H}{m}$
Complete step-by-step answer:
We will write the mathematical definition of latent heat and using the dimensions of the physical quantities involved in the equation, get the required dimensional formula for latent heat.
The latent heat $L$ of a body undergoing a phase change is the heat energy $H$ that is released or absorbed by a body of mass $m$ per unit mass.
$L=\dfrac{H}{m}$ --(1)
Now, let us write the dimensions of the physical quantities on the right hand side of equation (1).
$\left[ L \right]=\left[ \dfrac{H}{m} \right]=\dfrac{\left[ H \right]}{\left[ m \right]}$ --(2)
Now, heat is nothing but a form of energy. Therefore, it will have the same dimensional formula as that of energy. The dimensional formula for energy is $M{{L}^{2}}{{T}^{-2}}$.
$\therefore \left[ H \right]=M{{L}^{2}}{{T}^{-2}}$ --(3)
Now, the dimensional formula of mass is simply $M{{L}^{0}}{{T}^{0}}$.
$\therefore \left[ m \right]=M{{L}^{0}}{{T}^{0}}$ --(4)
Therefore, putting (3) and (4) in (2), we get
$\left[ L \right]=\dfrac{M{{L}^{2}}{{T}^{-2}}}{M{{L}^{0}}{{T}^{0}}}={{M}^{1-1}}{{L}^{2-0}}{{T}^{-2-0}}={{M}^{0}}{{L}^{2}}{{T}^{-2}}$
Hence, we have got the required dimensional formula for latent heat.
So, the correct answer is “Option A”.
Note: Students must not get confused and think that latent heat of vaporization and latent heat of fusion must have different dimensional formulae. Both of them are essentially latent heats involved during phase change. The only difference is that latent heat of fusion comes into action when there is a phase change between a solid and a liquid whereas the latent heat of vaporization comes into action when there is a phase change between the liquid state and the vapor state.
Formula used:
$L=\dfrac{H}{m}$
Complete step-by-step answer:
We will write the mathematical definition of latent heat and using the dimensions of the physical quantities involved in the equation, get the required dimensional formula for latent heat.
The latent heat $L$ of a body undergoing a phase change is the heat energy $H$ that is released or absorbed by a body of mass $m$ per unit mass.
$L=\dfrac{H}{m}$ --(1)
Now, let us write the dimensions of the physical quantities on the right hand side of equation (1).
$\left[ L \right]=\left[ \dfrac{H}{m} \right]=\dfrac{\left[ H \right]}{\left[ m \right]}$ --(2)
Now, heat is nothing but a form of energy. Therefore, it will have the same dimensional formula as that of energy. The dimensional formula for energy is $M{{L}^{2}}{{T}^{-2}}$.
$\therefore \left[ H \right]=M{{L}^{2}}{{T}^{-2}}$ --(3)
Now, the dimensional formula of mass is simply $M{{L}^{0}}{{T}^{0}}$.
$\therefore \left[ m \right]=M{{L}^{0}}{{T}^{0}}$ --(4)
Therefore, putting (3) and (4) in (2), we get
$\left[ L \right]=\dfrac{M{{L}^{2}}{{T}^{-2}}}{M{{L}^{0}}{{T}^{0}}}={{M}^{1-1}}{{L}^{2-0}}{{T}^{-2-0}}={{M}^{0}}{{L}^{2}}{{T}^{-2}}$
Hence, we have got the required dimensional formula for latent heat.
So, the correct answer is “Option A”.
Note: Students must not get confused and think that latent heat of vaporization and latent heat of fusion must have different dimensional formulae. Both of them are essentially latent heats involved during phase change. The only difference is that latent heat of fusion comes into action when there is a phase change between a solid and a liquid whereas the latent heat of vaporization comes into action when there is a phase change between the liquid state and the vapor state.
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Trending doubts
10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Explain zero factorial class 11 maths CBSE

What is a periderm How does periderm formation take class 11 biology CBSE

