
The dimension of $\sqrt {\dfrac{\mu }{\varepsilon }} $ where $\mu $ is permeability and $\varepsilon $ is permittivity is same as:
A) Resistance
B) Inductance
C) Capacitance
D) None of these
Answer
570.6k+ views
Hint: We are here considering the permeability and permittivity of that of a free space.
These have dimensional values that are already derived in terms of SI units.
Also,When the free space is considered, the permeability is the ability to make the flux line to pass though the space
.
Complete step by step answer:
The permeability is the ability of a body to pass magnetic lines through it. Its value depends on how much a particular body is permeable to the flux lines. The value of it varies accordingly with the materials. When the free space is considered, the permeability is the ability to make the flux line to pass though the space. The permittivity is the ability to make the electric field of lines to pass through the body. Like the permeability, the permittivity also changes with the materials. The permittivity of free space is the ability of the space to allow electric field lines to pass through.
The dimensional formula for permittivity is,
$[\varepsilon ] = [{M^{ - 1}}{L^{ - 3}}{T^4}{A^2}]$
The dimensional formula of permeability is,
$[\mu ] = [ML{T^{ - 2}}{A^{ - 2}}]$
Dividing the dimensional form of permeability by permittivity we get, $\dfrac{{[\mu ]}}{{[\varepsilon ]}} = \dfrac{{[ML{T^{ - 2}}{A^{ - 2}}]}}{{[{M^{ - 1}}{L^{ - 3}}{T^4}{A^2}]}} = [{M^2}{L^4}{T^{ - 6}}{A^{ - 4}}]$
Now taking the root of the above equation, we have
$\sqrt {\dfrac{{[\mu ]}}{{[\varepsilon ]}}} = \sqrt {[{M^2}{L^4}{T^{ - 6}}{A^{ - 4}}]} = [M{L^2}{T^{ - 3}}{A^{ - 2}}]$
Now, let us take the dimensional formula of resistance. We have,
$[R] = [M{L^2}{T^{ - 3}}{A^{ - 2}}]$
Thus, we can observe that the dimension of the square root of permeability divided permittivity is the same as that of resistance.
So, the correct answer is “Option A”.
Note:
As we can see from the definition that both the permeability and permittivity is the absence of the resistance. So, when one gets divided by the other the dimensional formula of resistance is observed. Also, we know that relative permittivity and permeability are unit-less entities.
These have dimensional values that are already derived in terms of SI units.
Also,When the free space is considered, the permeability is the ability to make the flux line to pass though the space
.
Complete step by step answer:
The permeability is the ability of a body to pass magnetic lines through it. Its value depends on how much a particular body is permeable to the flux lines. The value of it varies accordingly with the materials. When the free space is considered, the permeability is the ability to make the flux line to pass though the space. The permittivity is the ability to make the electric field of lines to pass through the body. Like the permeability, the permittivity also changes with the materials. The permittivity of free space is the ability of the space to allow electric field lines to pass through.
The dimensional formula for permittivity is,
$[\varepsilon ] = [{M^{ - 1}}{L^{ - 3}}{T^4}{A^2}]$
The dimensional formula of permeability is,
$[\mu ] = [ML{T^{ - 2}}{A^{ - 2}}]$
Dividing the dimensional form of permeability by permittivity we get, $\dfrac{{[\mu ]}}{{[\varepsilon ]}} = \dfrac{{[ML{T^{ - 2}}{A^{ - 2}}]}}{{[{M^{ - 1}}{L^{ - 3}}{T^4}{A^2}]}} = [{M^2}{L^4}{T^{ - 6}}{A^{ - 4}}]$
Now taking the root of the above equation, we have
$\sqrt {\dfrac{{[\mu ]}}{{[\varepsilon ]}}} = \sqrt {[{M^2}{L^4}{T^{ - 6}}{A^{ - 4}}]} = [M{L^2}{T^{ - 3}}{A^{ - 2}}]$
Now, let us take the dimensional formula of resistance. We have,
$[R] = [M{L^2}{T^{ - 3}}{A^{ - 2}}]$
Thus, we can observe that the dimension of the square root of permeability divided permittivity is the same as that of resistance.
So, the correct answer is “Option A”.
Note:
As we can see from the definition that both the permeability and permittivity is the absence of the resistance. So, when one gets divided by the other the dimensional formula of resistance is observed. Also, we know that relative permittivity and permeability are unit-less entities.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

