Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store
seo-qna
SearchIcon
banner

The dimension of magnetic field in M, L, T and C (Coulomb) is given as:
A. MLT1C1
B. MT2C2
C. MT1C1
D. MLT2C1

Answer
VerifiedVerified
522.6k+ views
2 likes
like imagedislike image
Hint: The dimensional formula of magnetic field can be calculated using the formula B=Fqv that has come from F=Bqv. This is the force acting on a charge q moving with velocity v in a magnetic field B.

Complete step by step answer:
To calculate the dimensional formula of magnetic field we take the formula
B=Fqv
This is the magnetic field B applied on a charge q, moving with a velocity v under the influence of a Magnetic Lorentz force F.
We must write each physical quantity used in its dimensional form:
Force F:
F=ma=[MLT2]
Charge q must be taken as Coulomb:
q=[C]
Velocity v:
v=[LT1]
Substituting these in the first equation we get:
B=[MLT2][C][LT1]
On solving we get:
B=[MT1C1]
Hence, the correct answer is option C. MT1C1
Additional Information:
The SI units and Dimensional formula of some important physical quantities to remember are:
Work, Energy of all kinds = J,[M1L2T2]
Power =W,[M1L2T3]
Planck’s Constant (h) = Js,[M1L2T1]
Angular displacement (θ)=rad,[M0L0T0].
Angular velocity (ω)=rads1[M0L0T0]
Force constant (forcedisplacement) = Nm1,[M1L0T2]
Coefficient of elasticity (stressstrain) = Nm2,[M1L1T2]
Angular frequency (ω)=,rads1[M0L0T1]
Angular momentum Iω=kgm2s1[M1L2T1]

Note: Another method for solving this question would be by using the formula for force on a current carrying conductor placed in a magnetic field F=BILand therefore, B=FIL .While solving dimensional formula questions students must note that every physical quantity must be expressed in its absolute units only.