
The dimension of frequency is:
$
(a){\text{ }}\left[ {{T^{ - 1}}} \right] \\
(b){\text{ }}\left[ {{M^0}{L^0}T} \right] \\
(c){\text{ }}\left[ {{M^0}{L^0}{T^{ - 2}}} \right] \\
(d){\text{ None of these}} \\
$
Answer
610.2k+ views
Hint: In this question use the concept that frequency is the inverse of time period and the dimension of time period is $\left[ T \right]$. So using the dimension of time dimension of frequency can be taken out.
Complete Step-by-Step solution:
As we know frequency (f) is inverse of time period (T).
$ \Rightarrow f = \dfrac{1}{T}$
$ \Rightarrow f = {T^{ - 1}}$
And we all know that the dimension of T is [T], one of the standard dimensions.
So the dimension of frequency is
$f = \left[ {{T^{ - 1}}} \right]$
So this is the required answer.
Hence option (A) is the correct answer.
Note – Frequency refers to the number of waves that passes a fixed point in unit time. It can also be defined as the number of cycles or vibrations undergone during one unit of time by a body undergoing a periodic form of motion in which it repeats itself after some regular or fixed interval of time.
Complete Step-by-Step solution:
As we know frequency (f) is inverse of time period (T).
$ \Rightarrow f = \dfrac{1}{T}$
$ \Rightarrow f = {T^{ - 1}}$
And we all know that the dimension of T is [T], one of the standard dimensions.
So the dimension of frequency is
$f = \left[ {{T^{ - 1}}} \right]$
So this is the required answer.
Hence option (A) is the correct answer.
Note – Frequency refers to the number of waves that passes a fixed point in unit time. It can also be defined as the number of cycles or vibrations undergone during one unit of time by a body undergoing a periodic form of motion in which it repeats itself after some regular or fixed interval of time.
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