The difference between the place value and face value of 5 in 91, 25,678 is
A. 4995
B. 0
C. 4095
D. 5000
Answer
633.3k+ views
Hint: Calculate place value of 5 by multiplying 5 with ${{10}^{n}}$ where ‘n’ is the position of 5 from left minus one. Face value of a number is the number itself. So, find the difference between the obtained place value of 5 and 5 to get the answer.
Complete step-by-step answer:
Given numbers = 91, 25,678
According to the question, we have to calculate the difference between place value and face value of ‘5’ in this number.
To find the required difference, first we need to find the place value and face value of ‘5’ in this number.
Every digit in a number has a place value. Place value is defined as the value represented by a digit in the number according to its position in the number.
Place value of a digit in a number$=digit\times {{10}^{x-1}}$, where $x$ is the position of the digit from left.
Hence, number\[=91,2\overset{4}{\mathop{5}}\,,\overset{3}{\mathop{6}}\,\overset{2}{\mathop{7}}\,\overset{1}{\mathop{8}}\,\]
Position of ‘5’ from left = 4
So, place value of $5=5\times {{10}^{4-1}}$
$\begin{align}
& =5\times {{10}^{3}} \\
& =5000 \\
\end{align}$
Now, we have to find the face value of ‘5’ in this number.
Face value of a digit in a number is the value of the digit itself.
So, face value of ‘5’ in 91, 25, 678 = 5
Now, difference of place value of ‘5’ in 91, 25, 678;
$\begin{align}
& =\left( place\ value\ of\ '5'\ in\ 91,25,678 \right)-\left( face\ value\ of\ '5'\ in\ 91,25,678 \right) \\
& =5000-5 \\
& =4995 \\
\end{align}$
Hence, the required difference between place value and face value of ‘5’ in 91, 25,678 is 4995 and option (c) will be the answer.
Note: To get the difference between place value and face value of a digit in the number, we always subtract face value from the place value.
As, the place value of a number is always greater than or equal to the face value of a digit in any number.
Complete step-by-step answer:
Given numbers = 91, 25,678
According to the question, we have to calculate the difference between place value and face value of ‘5’ in this number.
To find the required difference, first we need to find the place value and face value of ‘5’ in this number.
Every digit in a number has a place value. Place value is defined as the value represented by a digit in the number according to its position in the number.
Place value of a digit in a number$=digit\times {{10}^{x-1}}$, where $x$ is the position of the digit from left.
Hence, number\[=91,2\overset{4}{\mathop{5}}\,,\overset{3}{\mathop{6}}\,\overset{2}{\mathop{7}}\,\overset{1}{\mathop{8}}\,\]
Position of ‘5’ from left = 4
So, place value of $5=5\times {{10}^{4-1}}$
$\begin{align}
& =5\times {{10}^{3}} \\
& =5000 \\
\end{align}$
Now, we have to find the face value of ‘5’ in this number.
Face value of a digit in a number is the value of the digit itself.
So, face value of ‘5’ in 91, 25, 678 = 5
Now, difference of place value of ‘5’ in 91, 25, 678;
$\begin{align}
& =\left( place\ value\ of\ '5'\ in\ 91,25,678 \right)-\left( face\ value\ of\ '5'\ in\ 91,25,678 \right) \\
& =5000-5 \\
& =4995 \\
\end{align}$
Hence, the required difference between place value and face value of ‘5’ in 91, 25,678 is 4995 and option (c) will be the answer.
Note: To get the difference between place value and face value of a digit in the number, we always subtract face value from the place value.
As, the place value of a number is always greater than or equal to the face value of a digit in any number.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 7 Social Science: Engaging Questions & Answers for Success

Master Class 7 Science: Engaging Questions & Answers for Success

Master Class 7 Maths: Engaging Questions & Answers for Success

Class 7 Question and Answer - Your Ultimate Solutions Guide

Master Class 9 Social Science: Engaging Questions & Answers for Success

Trending doubts
Convert 200 Million dollars in rupees class 7 maths CBSE

Full Form of IASDMIPSIFSIRSPOLICE class 7 social science CBSE

List of coprime numbers from 1 to 100 class 7 maths CBSE

How many thousands make a crore class 7 maths CBSE

What is a subcontinent class 7 social science CBSE

Differentiate between map and globe class 7 social science CBSE


