Question

The density of silver $(Ag)$ is $10.5000gc{m^{ - 3}}$. How do you find the mass of $Ag$ that occupies $965c{m^3}$ of space?

Answer 1

Hint: As we are very well aware with the term density which is basically given as the ratio of mass of any substance to the volume occupied by that substance. So, in order to calculate the mass of any substance we can rearrange the above statement where the product of density and volume gives the mass.


Complete step by step answer:
As we already know that the density is always defined in terms of mass and volume and it is generally given as the ratio of mass of a particular substance to the volume occupied by that substance and it is expressed as shown below:
$density = \dfrac{{mass}}{{volume}}$
In the question, we are given that the density of silver is $10.5000gc{m^{ - 3}}$ and the volume occupied by silver is given $965c{m^3}$. As the units are similar in both density and volume so we need not to change these units of these quantities.
Now, to find out the mass of silver that occupies the given volume of space, we will rearrange the formula of density as shown below:
$mass = density \times volume$
Now, we got the mass to be calculated, so, after putting the given values from the question in this formula, we would get:
$mass = 10.5000 \times 965$
$mass = 1.01 \times {10^4}g$

Therefore, the correct answer is $1.01 \times {10^4}g$.

Note:Always remember that the mass is generally expressed in grams or kilograms units, volume is expressed in millimeters or cubic centimeters units and density is expressed in gram per millilitres or gram per cubic centimeters units. And the mass is directly related to the density of any substance and volume is inversely related to the density of the substance.