
The density of chlorine relative to air is:
A. $2.44$
B. $3$
C. found only experimentally
D. $4$
Answer
569.1k+ views
Hint: Vapor density is the density of a vapor in relation to that of hydrogen. It may be defined as the mass of a certain volume of a substance divided by mass of the same volume of hydrogen. The relative density is slightly different from the vapor density as the relative density is the density of any gas with respect to the density of any other random gas whereas the vapor density is the density of a gas with respect to only hydrogen gas.
Complete step by step answer:
As per the question, we have to determine the relative density of the chlorine with respect to the air. Relative density is a relative term and can be defined as the ratio of the molecular mass of one gas with respect to the molecular mass of another gas. This can be written mathematically as:
$R.D = \dfrac{{{M_{Cl}}}}{{{M_{air}}}}$
Where,$R.D = $Relative density
${M_{Cl}} = $ Molecular mass of chlorine = $2 \times 35.5 = 71$
${M_{air}} = $ Molecular mass of air = $29$ (experimentally determined)
Hence, substituting the values and on solving, we have:
$R.D = \dfrac{{71}}{{29}} = 2.44$
So, the correct answer is Option A.
Note:
The vapor density indicates whether a gas is denser (greater than one) or less dense (less than one) than air. The density has implications for container storage and personnel safety if a container can release a dense gas, its vapor could sink and, if flammable, collect until it is at a concentration sufficient for ignition. Even if not flammable, it could collect in the lower floor or level of a confined space and displace air, possibly presenting an asphyxiation hazard to individuals entering the lower part of that space.
Complete step by step answer:
As per the question, we have to determine the relative density of the chlorine with respect to the air. Relative density is a relative term and can be defined as the ratio of the molecular mass of one gas with respect to the molecular mass of another gas. This can be written mathematically as:
$R.D = \dfrac{{{M_{Cl}}}}{{{M_{air}}}}$
Where,$R.D = $Relative density
${M_{Cl}} = $ Molecular mass of chlorine = $2 \times 35.5 = 71$
${M_{air}} = $ Molecular mass of air = $29$ (experimentally determined)
Hence, substituting the values and on solving, we have:
$R.D = \dfrac{{71}}{{29}} = 2.44$
So, the correct answer is Option A.
Note:
The vapor density indicates whether a gas is denser (greater than one) or less dense (less than one) than air. The density has implications for container storage and personnel safety if a container can release a dense gas, its vapor could sink and, if flammable, collect until it is at a concentration sufficient for ignition. Even if not flammable, it could collect in the lower floor or level of a confined space and displace air, possibly presenting an asphyxiation hazard to individuals entering the lower part of that space.
Recently Updated Pages
The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Differentiate between action potential and resting class 12 biology CBSE

Two plane mirrors arranged at right angles to each class 12 physics CBSE

Which of the following molecules is are chiral A I class 12 chemistry CBSE

Name different types of neurons and give one function class 12 biology CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

Discuss the various forms of bacteria class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

An example of chemosynthetic bacteria is A E coli B class 11 biology CBSE

