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The density of aluminum is \[2700\dfrac{{kg}}{{{m^3}}}\].calculate as the mass of a block of aluminum which has a mass of\[20c{m^3}\]?

Answer
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Hint: The density (greater precisely, the volumetric mass density; additionally called unique mass), of a substance, is its mass according to unit quantity. The image most typically used for density is. The reciprocal of the density of a substance is every so often mentioned as its unique quantity, a period of time every now then utilized in thermodynamics. Density is thorough assets therein growing the number of a substance do now not boom its density; as a substitute, it'll increase its mass.

Complete Answer:
The mass of the block of aluminum is 54 grams.
The density of aluminum, which is \[2700\dfrac{{kg}}{{{m^3}}}\], i.e. mass per cubic meter. However, the dimensions of the block of aluminum are given in cubic centimeters. Hence, we should convert volume into cubic meters. As
 \[
  1cm = 0.01m \\
   = \dfrac{1}{{100}}m \\
 \]
We have 1 cubic centimeter equal to \[\dfrac{1}{{1000000}}\] cubic meters
And,
\[20c{m^3} = \dfrac{{20}}{{1000000}}{m^3}\]

As \[Mass = Density \times Volume\]
The mass of a block of aluminum\[20c{m^3}\] is
\[
   = \dfrac{{20}}{{1000000}} \times 2700kg \\
   = \dfrac{{54}}{{1000}}kg \\
   = 54grams \\
 \]
The density in any respect factors of a homogeneous item equals its general mass divided via way of means of its general quantity. The mass is usually measured with a scale or balance; the number is often measured directly (from the geometry of the item) or via way of means of the displacement of a fluid.

Note:
In general, density could also be modified via way of means of converting both the strain and therefore the temperature. Increasing the strain usually will increase the density of a cloth. Increasing the temperature commonly decreases the density; however, there are fantastic exceptions to the present generalization. For instance, the density of water will increase among its melting factor at; comparable conduct is decided in silicon at low temperatures.