
The density (in ${\text{g m}}{{\text{L}}^{{\text{ - 1}}}}$) of a \[{\text{3}}{\text{.6 M}}\] sulphuric acid solution having \[29\% \]$ {{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}$ [molar mass =\[{\text{98 gmo}}{{\text{l}}^{{\text{ - 1}}}}\]] by mass, will be:
1. \[{\text{1}}{\text{.45}}\]
2. \[{\text{1}}{\text{.65}}\]
3. \[{\text{1}}{\text{.88}}\]
4. \[{\text{1}}{\text{.22}}\]
Answer
513k+ views
Hint:Density is the ratio of mass of the solution and volume of solution. By introducing this ratio into the molarity of solution formula then we can find the density of the solution by using the given mass percent and molarity values of the solution.
Complete step by step answer:
From the given,
Molarity of solution = \[{\text{3}}{\text{.6 M}}\]
Means one litre of solution contains \[{\text{3}}{\text{.6 }}\] moles of sulfuric acid.
Molar mass of sulfuric acid = \[{\text{98 g/mol}}\]
One litre of solution contains \[{\text{3}}{\text{.6 X 98 gms of }}{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}\].
Mass percent of solution = \[{\text{29% }}\]
Means 100 grams of solution contains \[{\text{29}}\] grams of sulfuric acid.
Let’s calculate the density of solution;
\[{\text{Molarity of the solution = }}\dfrac{{{\text{Moles of solute}}}}{{{\text{Volume of solution in Litres}}}}\]……………………..(1)
\[{\text{Volume of solution = }}\dfrac{{{\text{Mass}}}}{{{\text{Density}}}}\]……………………………….(2)
From equation (1) and (2)
\[{\text{Molarity of the solution = }}\dfrac{{{\text{Moles of solute}}}}{{\dfrac{{{\text{Mass}}}}{{{\text{Density}}}} X 1000}}\]
\[{\text{Molarity of the solution = }}\dfrac{{{\text{Moles of solute X Density}}}}{{{\text{Mass}}}} X 1000\]………………………………(3)
Substitute the all given values in equation (3)
\[{\text{3}}{\text{.6 X 98 = }}\dfrac{{{\text{29 X Density}}}}{{{\text{100}}}}{\text{ X 1000}}\]
\[{\text{Density = }}\dfrac{{{\text{352}}{\text{.8}}}}{{{\text{290}}}}{\text{ = 1}}{\text{.22g/ml}}\]
Hence, the answer is \[{\text{d = 1}}{\text{.22 g/ml}}\].
Therefore, the correct option is (4).
Additional information:
Molarity and molality are the ways to measure the concentration of a chemical solution. The main difference between the two comes down to mass versus quantity.
Molality describes the moles of a solvent with respect to the mass of a solvent, whereas molarity describes the moles of a solvent in relation with the volume of a solution.
Note:
The mass percent describes the component of elements in a particular mixture. During a given mass of solution, it shows the mass of solute present.
Complete step by step answer:
From the given,
Molarity of solution = \[{\text{3}}{\text{.6 M}}\]
Means one litre of solution contains \[{\text{3}}{\text{.6 }}\] moles of sulfuric acid.
Molar mass of sulfuric acid = \[{\text{98 g/mol}}\]
One litre of solution contains \[{\text{3}}{\text{.6 X 98 gms of }}{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}\].
Mass percent of solution = \[{\text{29% }}\]
Means 100 grams of solution contains \[{\text{29}}\] grams of sulfuric acid.
Let’s calculate the density of solution;
\[{\text{Molarity of the solution = }}\dfrac{{{\text{Moles of solute}}}}{{{\text{Volume of solution in Litres}}}}\]……………………..(1)
\[{\text{Volume of solution = }}\dfrac{{{\text{Mass}}}}{{{\text{Density}}}}\]……………………………….(2)
From equation (1) and (2)
\[{\text{Molarity of the solution = }}\dfrac{{{\text{Moles of solute}}}}{{\dfrac{{{\text{Mass}}}}{{{\text{Density}}}} X 1000}}\]
\[{\text{Molarity of the solution = }}\dfrac{{{\text{Moles of solute X Density}}}}{{{\text{Mass}}}} X 1000\]………………………………(3)
Substitute the all given values in equation (3)
\[{\text{3}}{\text{.6 X 98 = }}\dfrac{{{\text{29 X Density}}}}{{{\text{100}}}}{\text{ X 1000}}\]
\[{\text{Density = }}\dfrac{{{\text{352}}{\text{.8}}}}{{{\text{290}}}}{\text{ = 1}}{\text{.22g/ml}}\]
Hence, the answer is \[{\text{d = 1}}{\text{.22 g/ml}}\].
Therefore, the correct option is (4).
Additional information:
Molarity and molality are the ways to measure the concentration of a chemical solution. The main difference between the two comes down to mass versus quantity.
Molality describes the moles of a solvent with respect to the mass of a solvent, whereas molarity describes the moles of a solvent in relation with the volume of a solution.
Note:
The mass percent describes the component of elements in a particular mixture. During a given mass of solution, it shows the mass of solute present.
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Trending doubts
1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

At which age domestication of animals started A Neolithic class 11 social science CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE
