The daily recommended serving of protein is 50 grams. A nutritional store contains 32% of the daily recommended serving of protein and 10% of the daily recommending serving of fat. If the nutritional store contains 700% more grams of protein than grams of fat, find the daily recommended serving fat ( in grams ).
(a) 20
(b) 15
(c) 12
(d) 27
Answer
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Hint: To solve this question firstly, we will find the amount of protein in bar and then we will determine the fat in bar by percent change equation : percent change that is $\dfrac{difference}{original}\times 100$. Then, once we get fat in a bar, we will find the daily recommended fat serving using the statement 10% of the daily recommending serving of fat.
Complete step-by-step answer:
First, we will determine the grams of protein in the bar.
Now, if the bar contains 32% of the daily recommended serving of protein and the daily recommended serving of protein in 50 gm, then the bar contains $0.32\times 50=16$ gm of protein.
Next , we will determine the gm of fat in the bar by using the percent change equation : percent change
That is $\dfrac{difference}{original}\times 100$
The percent change is 700%, and the original is the gm of fats as percent more means the original is the smaller number, which means
$700=\dfrac{16-x}{x}\times 100$
Divide both side by 100, we get
$7=\dfrac{16-x}{x}$
On simplifying using cross multiplication, we get
$7x=16-x$
8x = 16
Or, x = 2, which is equal to the number of fat in the bar.
Now, to find the daily recommended serving of fat, we have 2 is 10% of the daily recommended serving.
So, if the daily recommended serving of fat is y,
Then, $2=\dfrac{10}{100}\times y$
On simplifying, we get
$2=\dfrac{1}{10}\times y$
Or, y = 20 gm
So, the daily recommended serving of fat is 20 gm.
So, the correct answer is “Option a”.
Note: To solve such a question, understanding of language of question is must and one must take out as much as information from the question. Calculation must be done correctly while doing cross multiplication. Always put units of mass after the final numerical answer. Try to avoid calculation mistakes.
Complete step-by-step answer:
First, we will determine the grams of protein in the bar.
Now, if the bar contains 32% of the daily recommended serving of protein and the daily recommended serving of protein in 50 gm, then the bar contains $0.32\times 50=16$ gm of protein.
Next , we will determine the gm of fat in the bar by using the percent change equation : percent change
That is $\dfrac{difference}{original}\times 100$
The percent change is 700%, and the original is the gm of fats as percent more means the original is the smaller number, which means
$700=\dfrac{16-x}{x}\times 100$
Divide both side by 100, we get
$7=\dfrac{16-x}{x}$
On simplifying using cross multiplication, we get
$7x=16-x$
8x = 16
Or, x = 2, which is equal to the number of fat in the bar.
Now, to find the daily recommended serving of fat, we have 2 is 10% of the daily recommended serving.
So, if the daily recommended serving of fat is y,
Then, $2=\dfrac{10}{100}\times y$
On simplifying, we get
$2=\dfrac{1}{10}\times y$
Or, y = 20 gm
So, the daily recommended serving of fat is 20 gm.
So, the correct answer is “Option a”.
Note: To solve such a question, understanding of language of question is must and one must take out as much as information from the question. Calculation must be done correctly while doing cross multiplication. Always put units of mass after the final numerical answer. Try to avoid calculation mistakes.
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