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The correct order of the atomic radii of C, Cs, Al and S is:
(a) $S$ < $C$ < $Al$ < $Cs$
(b) $S$ < $C$ < $Cs$ < $Al$
(c) $C$ < $S$ < $Cs$ < $Al$
(d)$C$ < $S$ < $Al$ < $Cs$

Answer
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Hint: As we move from left to right, atomic radii decreases and as we move from top to bottom, the atomic radii increases, so identify the positions of these elements in the periodic table and then, you can easily find the increasing order of atomic radii in these elements.

Complete answer:
First of all, let's discuss what an atomic radius is. By the term atomic radius, we mean the average distance of the outermost shell from the nucleus.
The atomic decreases as we move from right to left of the periodic table and increases as we move from top to bottom of the periodic table.
The increasing order of the atomic radii of the elements C, Cs, Al and S can be easily determined with the help of the periodic table as:

1 H2 He
3Li 4Be5 B6 C7 N8 O9 F10 Ne
11Na12Mg13 Al14 Si15 P16 S17 Cl18 Ar
19K20Ca21Sc22Ti23 V24 Cr25 Mn26 Fe27 Co28 Ni29 Cu30 Zn31 Ga32 Ge33 As34 Se35 Br36 Kr
37Rb38Sr39Y40 Zr41 Nb42 Mo43 Tc44 Ru45 Rh46 Pd47 Ag48 Cd49 In50 Sn51 Sb52 Te53 I54 Xe
55Cs56Ba57La72 Hf73 Ta74 W75 Re76 Os77Ir78 Pt79 Au80 Hg81 Tl82 Pb83 Bi84 Po85 At86 Rn


From the periodic table , we can see that the Cs( cesium) has the largest atomic radii among all, followed by aluminum; Al then carbon; C and Sulphur; S has the smallest atomic radii of all. So, the increasing order of atomic radii is;
$S$ < $C$ < $Al$ < $Cs$

Hence, option(a) is correct.

Note:
Atomic radii s divided into three types;
1. Covalent radius : the distance between the two atoms when they are bound by a single bond in a covalent molecule is called the covalent radius.
2. Van Der Waals radius: the one half the distance between the nuclei of the two non covalently bonded atoms is called the Van Der Waals radius.
3. Metallic radius: it is one half the internuclear distance between the two adjacent metal atoms.