Question

The correct order of solubility of the following compound in water is:
A.$Ba{(OH)_2} < Mg{(OH)_2}$
B.$BaC{O_3} > CaC{O_3}$
C.$Ca{(OH)_2} = Mg{(OH)_2}$
D.$CaS{O_4} < MgS{O_4}$

Answer 1

Hint: Solubility is that property of a solid, liquid or evaporated chemical substance that area unit referred to as substance to dissolve during a solid, liquid or evaporated solvent. The solubility of a substance depends on the physical and chemical properties of the solute and solvent additionally on temperature, pressure and presence of different chemicals of the solution.

Complete step by step solution:
Solubility of the Hydroxides-
Group $2$ metal hydroxides become additional soluble in water as you go down the column. This trend may be explained by the decrease within the lattice energy of the hydroxide salt and by the rise in the coordination number of the metal ion as you go down the column.
Solubility of the sulfates-
The sulfates are less soluble down the group.
Solubility of the carbonates-
The carbonates are less soluble down the group. All the Group two carbonates are highly soluble. Magnesium carbonate. There is less knowledge for beryllium carbonate, however it does react with water, the trend is obscured. The trend to lower solubility is, however, broken at rock bottom of the group: barium carbonate is slightly higher soluble than strontium sulfate. There are not any easy samples of this trend.
Then, $MgS{O_4}$ is quickly soluble in water. With increase in size of the central metal particle, the solubility of the sulphates of alkaline earth metals decreases as the hydration enthalpy from $B{e^{2 + }}$ to $B{a^{2 + }}$ decreases down the group. Therefore, $MgS{O_4}$ is highly and more soluble in water than $CaS{O_4}$.

So the correct answer is D.

Note: The dissolvability request is $NaCl < LiCl < BeC{l_2}$. The request for the charge thickness is $N{a^ + },L{i^ + },B{i^{2 + }}$.This is an identical request wherever the hydration energy or association energy increments. And additionally more $BeC{l_2}$ is the most polar compound among the compound, consequently its solubility is higher than others.