Question

The correct order of increasing polarizing powder is:
A. $C{s^ + } > R{b^ + } > {K^ + } > N{a^ + }$
B. $B{e^{ + 2}} > M{g^{ + 2}} > C{a^{ + 2}} > S{r^{ + 2}}$
C. $B{a^{ + 2}} > S{r^{ + 2}} > C{a^{ + 2}} > M{g^{ + 2}}$
D. $L{i^{ + 2}} > N{a^{ + 2}} > {K^{ + 2}} > R{b^{ + 2}}$

Answer 1

Hint: The ability of a cation to distort an anion is known as its polarization and the tendency of the anion to become polarized by the cation is known for its polarizability. The high polarizing powder stems from the greater concentration of positive charge on a small area. This is figured out by the Fajan's rule. All the options are given in the cations which is the size of cations to figure out.

Complete step by step answer:
When reading about polar covalent bonds which predate electronegativity and make use of ionic and atomic radius data that was becoming available through X-ray. To use this rule to assume binary compounds and identify the potential cation and anion.
The statements are given below:
1. High charged and small size cation
2. High charge and large size of the anion
All cations are in decreasing order of polarizing powder which increases order of the size. It decreases the order of the charge. When we move the left to right in periodic table the size of atom decreases and when we move top to bottom the size of atoms increases.
According to this information the decreasing order of polarizing power is given below:
 $B{e^{ + 2}} > M{g^{ + 2}} > C{a^{ + 2}} > S{r^{ + 2}}$

Hence, option (B) is the correct answer.

Note: Polarization refers to an effect reducing the performance of batteries. Polarization powder of cation is the ability of cation to distort an anion. It becomes polarized which is known as polarizability, it can be described by the ability of the cation which attracts electron clouds towards itself.