
The correct IUPAC name of given compound is:
(A) $ 2 - $ formyl cyclopentane oic acid
(B) $ 2 - cyclopentyl - 1 - carboxylic $ acid
(C) $ 2 - formylcyclopen\tan e - 1 - carboxylic $ acid
(D) None of these
Answer
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Hint: There are certain rules for the naming of organic or inorganic compounds which are set by the IUPAC (International Union of Pure and Applied Chemistry). These rules need to be followed strictly while naming the chemical compounds. So, in the solution we will understand the step by step naming of the given organic compound.
Complete Step By Step Answer:
We will name the given organic compound in the step by step manner as follows:
- First, we identify the longest chain in the compound. In the given compound, the longest chain is cyclopentane.
- Now, numbering is done from the functional group which has greater priority than the rest of the functional groups present in the compound. Here, carboxylic acid has more priority than the aldehyde group and it will have a lower number.
So, in the above given compound, the carbon attached to carboxylic acid is given one number and the carbon attached to the aldehyde group is given the second number.
Therefore, based on the above rules, we can say that the IUPAC name of the above given compound is $ 2 - formylcyclopen\tan e - 1 - $ carboxylic acid.
Hence, the correct option is (C) $ 2 - formylcyclopen\tan e - 1 - $ carboxylic acid.
Note:
The priority order of different functional groups are Carboxylic acid> Amide> Aldehyde> Ketone> Alcohol> Amine> Alkyne> Alkene> Alkane. We should note that if the aldehyde group has first priority, then the suffix “-al” is added to the name of the longest chain and if it is not the first priority, then the prefix “formyl” is added to the compound.
Complete Step By Step Answer:
We will name the given organic compound in the step by step manner as follows:
- First, we identify the longest chain in the compound. In the given compound, the longest chain is cyclopentane.
- Now, numbering is done from the functional group which has greater priority than the rest of the functional groups present in the compound. Here, carboxylic acid has more priority than the aldehyde group and it will have a lower number.
So, in the above given compound, the carbon attached to carboxylic acid is given one number and the carbon attached to the aldehyde group is given the second number.
Therefore, based on the above rules, we can say that the IUPAC name of the above given compound is $ 2 - formylcyclopen\tan e - 1 - $ carboxylic acid.
Hence, the correct option is (C) $ 2 - formylcyclopen\tan e - 1 - $ carboxylic acid.
Note:
The priority order of different functional groups are Carboxylic acid> Amide> Aldehyde> Ketone> Alcohol> Amine> Alkyne> Alkene> Alkane. We should note that if the aldehyde group has first priority, then the suffix “-al” is added to the name of the longest chain and if it is not the first priority, then the prefix “formyl” is added to the compound.
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