
The coordinates of the vertices of a rectangle are \[\left( { - 3,5} \right),\left( {0, - 4} \right),\left( {3,7} \right),\left( {6, - 2} \right)\]? How do you find the area of this figure?
Answer
561k+ views
Hint:
In the given question, we have been given the coordinates of the vertices of a rectangle. We have to calculate the area of the figure formed by these points. To do that, we first draw a rough figure of the configuration. Then we find the length of the two unequal sides of the rectangle using the distance formula. And then finally, after calculating the lengths, we just multiply them to find the area of the given rectangular figure.
Formula Used:
1) We are going to use the distance formula:
Let there be two points \[\left( {{x_1},{y_1}} \right)\] and \[\left( {{x_2},{y_2}} \right)\]. Then 2) The distance between the points is:
\[{d_i} = \sqrt {{{\left( {{y_2} - {y_1}} \right)}^2} + {{\left( {{x_2} - {x_1}} \right)}^2}} \]
Complete step by step solution:
Consider the following triangle with the given vertices and coordinates.
Now, let us calculate the lengths of any two adjacent (hence, unequal) sides of the rectangle \[ABCD\]. Let us calculate the lengths of sides \[AB\] and \[BC\].
First, let us find the length of side \[AB\]:
Coordinates between the two points are \[\left( {0, - 4} \right)\] and \[\left( { - 3,5} \right)\].
Hence, \[AB = \sqrt {{{\left( { - 3 - 0} \right)}^2} + {{\left( {5 - \left( { - 4} \right)} \right)}^2}} = \sqrt {9 + 81} = \sqrt {90} = 3\sqrt {10} \] units
Similarly, for the side \[BC\], coordinates are \[\left( { - 3,5} \right)\] and \[\left( {3,7} \right)\].
Hence, \[BC = \sqrt {{{\left( { - 3 - 3} \right)}^2} + {{\left( {5 - 7} \right)}^2}} = \sqrt {36 + 4} = \sqrt {40} = 2\sqrt {10} \] units
Thus, the area of rectangle \[ABCD\] is,
\[area = 3\sqrt {10} \times 2\sqrt {10} = 6 \times 10 = 60\] square units
Note:
For solving questions of such type, we first write what has been given to us. Then we write down what we have to find. Then we write the formula which connects the two things. It is advised that we always draw the figure of the configuration first, so that we know what thing we are dealing with. Then, we calculate the distance between the two points. This distance between any two given points is the length of the side joining two points.
In the given question, we have been given the coordinates of the vertices of a rectangle. We have to calculate the area of the figure formed by these points. To do that, we first draw a rough figure of the configuration. Then we find the length of the two unequal sides of the rectangle using the distance formula. And then finally, after calculating the lengths, we just multiply them to find the area of the given rectangular figure.
Formula Used:
1) We are going to use the distance formula:
Let there be two points \[\left( {{x_1},{y_1}} \right)\] and \[\left( {{x_2},{y_2}} \right)\]. Then 2) The distance between the points is:
\[{d_i} = \sqrt {{{\left( {{y_2} - {y_1}} \right)}^2} + {{\left( {{x_2} - {x_1}} \right)}^2}} \]
Complete step by step solution:
Consider the following triangle with the given vertices and coordinates.
Now, let us calculate the lengths of any two adjacent (hence, unequal) sides of the rectangle \[ABCD\]. Let us calculate the lengths of sides \[AB\] and \[BC\].
First, let us find the length of side \[AB\]:
Coordinates between the two points are \[\left( {0, - 4} \right)\] and \[\left( { - 3,5} \right)\].
Hence, \[AB = \sqrt {{{\left( { - 3 - 0} \right)}^2} + {{\left( {5 - \left( { - 4} \right)} \right)}^2}} = \sqrt {9 + 81} = \sqrt {90} = 3\sqrt {10} \] units
Similarly, for the side \[BC\], coordinates are \[\left( { - 3,5} \right)\] and \[\left( {3,7} \right)\].
Hence, \[BC = \sqrt {{{\left( { - 3 - 3} \right)}^2} + {{\left( {5 - 7} \right)}^2}} = \sqrt {36 + 4} = \sqrt {40} = 2\sqrt {10} \] units
Thus, the area of rectangle \[ABCD\] is,
\[area = 3\sqrt {10} \times 2\sqrt {10} = 6 \times 10 = 60\] square units
Note:
For solving questions of such type, we first write what has been given to us. Then we write down what we have to find. Then we write the formula which connects the two things. It is advised that we always draw the figure of the configuration first, so that we know what thing we are dealing with. Then, we calculate the distance between the two points. This distance between any two given points is the length of the side joining two points.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

