The compound T is:
(A) Glycine.
(B) Alanine.
(C) Valine.
(D) Serine.
Answer
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Hint: The resonance structures of Alanine are drawn by first displacing the lone pair of electrons on the nitrogen to the bond between $ C $ and $ N. $ This results in formation of a double bond between $ C $ and $ N $ with $ N $ getting a positive charge due to the donation of electrons.
Complete answer:
Alanine has the chemical formula $ C{{H}_{3}}-CH(N{{H}_{2}})-COOH $. It is an organic compound that consists of a phenyl group attached to an amine group. Alanine is considered to be the simplest aromatic amine. Alanine has the odour of a rotten.
The chemical reaction is given by;
The valency of $ C $ is $ 4. $ This means that $ C $ can form $ 4 $ bonds. As $ C-1 $ already had $ 4 $ bonds, the electrons on $ C=C $ pi bond move to the adjacent $ C-2 $ atom and the $ C-2 $ atom gets a negative charge. This is how the second structure is formed.
Similarly, the negative on the $ C-2 $ atom will displace to the adjacent bond. The pi electrons on the adjacent bond then move to the $ C-4 $ atom and it gets a negative charge. This is how the third structure is formed.
Next, the negative on the $ C-4 $ atom will displace to the adjacent bond. The pi electrons on the adjacent bond then move to the $ C-6 $ atom and it gets a negative charge. This is how the T structure is formed.
Therefore, Correct answer is option B i.e., Alanine.
Note:
Alanine has a wide range of uses.
-It is used in rubber accelerators and antioxidants.
-Alanine is also an ingredient in dyes.
-It is used in pharmaceuticals and petroleum refining
Complete answer:
Alanine has the chemical formula $ C{{H}_{3}}-CH(N{{H}_{2}})-COOH $. It is an organic compound that consists of a phenyl group attached to an amine group. Alanine is considered to be the simplest aromatic amine. Alanine has the odour of a rotten.
The chemical reaction is given by;
The valency of $ C $ is $ 4. $ This means that $ C $ can form $ 4 $ bonds. As $ C-1 $ already had $ 4 $ bonds, the electrons on $ C=C $ pi bond move to the adjacent $ C-2 $ atom and the $ C-2 $ atom gets a negative charge. This is how the second structure is formed.
Similarly, the negative on the $ C-2 $ atom will displace to the adjacent bond. The pi electrons on the adjacent bond then move to the $ C-4 $ atom and it gets a negative charge. This is how the third structure is formed.
Next, the negative on the $ C-4 $ atom will displace to the adjacent bond. The pi electrons on the adjacent bond then move to the $ C-6 $ atom and it gets a negative charge. This is how the T structure is formed.
Therefore, Correct answer is option B i.e., Alanine.
Note:
Alanine has a wide range of uses.
-It is used in rubber accelerators and antioxidants.
-Alanine is also an ingredient in dyes.
-It is used in pharmaceuticals and petroleum refining
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