The compound interest on Rs. 8000 for 1 year at 5 %p.a. payable half-yearly is:
\[
\left( a \right)Rs.800 \\
\left( b \right)Rs.810 \\
\left( c \right)Rs.400 \\
\left( d \right)Rs.405 \\
\]
Answer
642.3k+ views
Hint-In this question, we use the concept of compound interest. We use formula of Compound interest = Amount - Principal and ${\text{Amount}} = P{\left( {1 + \dfrac{R}{{100}}} \right)^t}$ where, P is principal, R is rate and t is time.
Complete step-by-step solution -
Given, Principal (P) =Rs.8000
Rate (R) = 5% payable half yearly
Time (t) = 1 year
Now, we have to find the amount for half yearly so the rate becomes half and time becomes double for half yearly.
$
\Rightarrow {\text{Amount}} = P{\left( {1 + \dfrac{R}{{100}}} \right)^t} \\
\Rightarrow {\text{Amount}} = 8000{\left( {1 + \dfrac{5}{{2 \times 100}}} \right)^2} \\
\Rightarrow {\text{Amount}} = 8000{\left( {1 + \dfrac{1}{{40}}} \right)^2} \\
\Rightarrow {\text{Amount}} = 8000{\left( {\dfrac{{41}}{{40}}} \right)^2} \\
\Rightarrow {\text{Amount}} = 8000 \times \dfrac{{41}}{{40}} \times \dfrac{{41}}{{40}} \\
\Rightarrow {\text{Amount}} = 5 \times 41 \times 41 \\
\Rightarrow {\text{Amount}} = Rs.8405 \\
$
Now, we use the formula of compound interest.
$
{\text{Compound interest}} = {\text{Amount}} - {\text{Principal}} \\
\Rightarrow {\text{Compound interest}} = 8405 - 8000 \\
\Rightarrow {\text{Compound interest}} = Rs.405 \\
$
So, the correct option is (d).
Note-In such types of problems first we find the value of the amount for half yearly and always remember one thing for half yearly rate becomes half and time becomes double of actual value and then uses compound interest formula. So, we will get the required answer.
Complete step-by-step solution -
Given, Principal (P) =Rs.8000
Rate (R) = 5% payable half yearly
Time (t) = 1 year
Now, we have to find the amount for half yearly so the rate becomes half and time becomes double for half yearly.
$
\Rightarrow {\text{Amount}} = P{\left( {1 + \dfrac{R}{{100}}} \right)^t} \\
\Rightarrow {\text{Amount}} = 8000{\left( {1 + \dfrac{5}{{2 \times 100}}} \right)^2} \\
\Rightarrow {\text{Amount}} = 8000{\left( {1 + \dfrac{1}{{40}}} \right)^2} \\
\Rightarrow {\text{Amount}} = 8000{\left( {\dfrac{{41}}{{40}}} \right)^2} \\
\Rightarrow {\text{Amount}} = 8000 \times \dfrac{{41}}{{40}} \times \dfrac{{41}}{{40}} \\
\Rightarrow {\text{Amount}} = 5 \times 41 \times 41 \\
\Rightarrow {\text{Amount}} = Rs.8405 \\
$
Now, we use the formula of compound interest.
$
{\text{Compound interest}} = {\text{Amount}} - {\text{Principal}} \\
\Rightarrow {\text{Compound interest}} = 8405 - 8000 \\
\Rightarrow {\text{Compound interest}} = Rs.405 \\
$
So, the correct option is (d).
Note-In such types of problems first we find the value of the amount for half yearly and always remember one thing for half yearly rate becomes half and time becomes double of actual value and then uses compound interest formula. So, we will get the required answer.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
What is BLO What is the full form of BLO class 8 social science CBSE

What are the 12 elements of nature class 8 chemistry CBSE

Citizens of India can vote at the age of A 18 years class 8 social science CBSE

Right to vote is a AFundamental Right BFundamental class 8 social science CBSE

Advantages and disadvantages of science

Full form of STD, ISD and PCO

