Question

What would be the compound formula of strontium Bromide?

Answer 1

Hint: We know that strontium is a group 2 element. Strontium symbol is Sr. because it is a group 2 element so its valency is $+2$ . And these group 2 elements are ionic. We know that bromine is a p-block element so it has $-1$ valency. Hence the compound formula for strontium bromide will be $SrB{r}_2$

Complete Step By Step Answer:
As we know that Sr is a group 2 element. Group 2 elements are known as alkaline earth metals. Since these elements' electronic configuration is $n{s}^2$ so these elements have $+2$ a positive charge. And compounds of these elements are ionic. It means that these elements make an ionic compound. Sr atomic number is $38$ and its atomic mass is $87.62gmo{l}^{-1}$ .
Now, we know that Br is the p-block element and its atomic number is 35. Since its electronic configuration is $\left[Ar\right]4s^{2}3d^{10}4p^5$ so bromine has 7 valence electrons so it has $-1$ charge. Bromine is also ionic. Bromine has a negative charge.
Now we will discuss the reactivity of strontium towards bromine. All the alkaline earth metals react with halogen by the simple reaction at elevated temperature.
 $M+X_2\to M{X}_2$
Here M= metal, X= halogen ( F, Cl, Br, I )
The reaction of strontium with bromine-
 $S{r}_{(s)}+B{r}_{2(l)}\to SrB{r}_{2(s)}$
Hence the formula of strontium bromide would be $SrB{r}_2$ .
Since it is an ionic compound. It is odorless.
On flame test, it burns with a bright red color flame. It is used as flares for signaling etc.

Note:
Strontium has $+2$ a positive charge and bromine has $-1$ a negative charge and they combine to form an ionic compound $SrB{r}_2$ . Since strontium is alkaline earth metal and bromine is non-metal so they form an ionic compound. $SrB{r}_2$ has some pharmaceutical uses. It is white crystalline salt.