
The compound formed by reaction of ethylene glycol and periodic acid $(HI{O_4})$ is:
A.Carbon dioxide
B.Formic acid
C.Formaldehyde
D.glyoxal
Answer
531.3k+ views
Hint: In the given question we have to find out what products or products would form on the conduction of given reaction. Now we know that periodic acid $(HI{O_4})$ is an oxidising agent and the molecule of ethylene glycol can be easily oxidised by it that would lead to the formation of the semi obtained products and later the final product that is methanal.
Complete answer:
The given question is asked about the product that would form when the reaction of ethylene glycol and periodic acid will take place. Here we have to use the basic chemistry to solve the given question by solving the chemical reaction of the given reactants.
Now we have to do step by step solution of the reaction and then we can get the answer:
Step1: Give the correct formula of the reactants :
Chemical formula of ethylene glycol : \[{(C{H_2}OH)_2}\]
Chemical formula of periodic acid : \[HI{O_4}\]
Step2: Now we have to write the correct balanced chemical reaction for the question.
\[{(C{H_2}OH)_2} + 2HI{O_4} \to 2C{H_2}{(OH)_2} \to 2{H_2}O + 2HCHO\]
Here the reaction will take place and basically the periodic acid would be an oxidising agent that will break the glycosidic linkage and at that place will provide the $ - OH$ connections.
Now these connections will further change and the molecules of water will be dissipated from the products to find the stable product.
Therefore the right answer would be option C, Formaldehyde which is also called methanal.
Note:
Periodic acid is the highest oxoacid of iodine, in which the iodine exists in an oxidation state \[ + 7\] . Like all periodates it can exist in two forms: orthoperiodic acid, with the chemical formula \[{H_5}I{O_6}\] and meta periodic acid, which has the formula \[HI{O_4}\] . Periodic acid was discovered by Heinrich Gustav Magnus and C. F. Ammermüller in \[1833\] .
Complete answer:
The given question is asked about the product that would form when the reaction of ethylene glycol and periodic acid will take place. Here we have to use the basic chemistry to solve the given question by solving the chemical reaction of the given reactants.
Now we have to do step by step solution of the reaction and then we can get the answer:
Step1: Give the correct formula of the reactants :
Chemical formula of ethylene glycol : \[{(C{H_2}OH)_2}\]
Chemical formula of periodic acid : \[HI{O_4}\]
Step2: Now we have to write the correct balanced chemical reaction for the question.
\[{(C{H_2}OH)_2} + 2HI{O_4} \to 2C{H_2}{(OH)_2} \to 2{H_2}O + 2HCHO\]
Here the reaction will take place and basically the periodic acid would be an oxidising agent that will break the glycosidic linkage and at that place will provide the $ - OH$ connections.
Now these connections will further change and the molecules of water will be dissipated from the products to find the stable product.
Therefore the right answer would be option C, Formaldehyde which is also called methanal.
Note:
Periodic acid is the highest oxoacid of iodine, in which the iodine exists in an oxidation state \[ + 7\] . Like all periodates it can exist in two forms: orthoperiodic acid, with the chemical formula \[{H_5}I{O_6}\] and meta periodic acid, which has the formula \[HI{O_4}\] . Periodic acid was discovered by Heinrich Gustav Magnus and C. F. Ammermüller in \[1833\] .
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