
The compound (C) is:
Answer
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Hint :The compound given here is $ 5 - Hydroxy - 3 - hexanone $ which is treated with Sodium hypobromite to give product A which then is treated with hydronium ion to give product B. Product B is heated to obtain product C. we will see each reaction to understand the process and identify the products formed from each of the reaction.
Complete Step By Step Answer:
In the first reaction $ 5 - Hydroxy - 3 - hexanone is treated with Sodium hypobromite it will remove a methyl group and form alkyl halide and Sodium Hydroxide. The reaction taking place here is written as
In the above reaction $ 5 - Hydroxy - 3 - hexanone $ reacts with Sodium hypobromite to give Methyl bromide and $ 5 - Hydroxy - 3 - pentanone $ . So, the product A according to reaction is $ 5 - Hydroxy - 3 - pentanone $ .
Let's see the second reaction in which product A reacts with hydronium ion; in an oxidation reaction the alcohol is converted to carboxylic acid. The reaction taking place here is written as
In above reaction 5-hydroxy-2-pentanone undergoes oxidation reaction to form $ 3 - Oxopentanoicacid $ . So, the product B according to question is $ 5 - Hydroxy - 3 - pentanone $
Let's see the last reaction in which product B undergoes strong heating to remove carbon dioxide. It is also known as the decarboxylation reaction. the reaction taking place here is written as
In above reaction $ 3 - $ Oxopentanoicacid undergoes decarboxylation reaction in strong heating conditions to form Carbon dioxide and $ {\text{n}} - butanone $ . So, according to the question the product C is $ {\text{n}} - butanone $ .
Note :
Carefully observe the position of the functional group while writing a reaction because it is necessary for the product formation. Also pay attention to the conditions in which the reaction is carried out because it can affect the reaction.
Complete Step By Step Answer:
In the first reaction $ 5 - Hydroxy - 3 - hexanone is treated with Sodium hypobromite it will remove a methyl group and form alkyl halide and Sodium Hydroxide. The reaction taking place here is written as
In the above reaction $ 5 - Hydroxy - 3 - hexanone $ reacts with Sodium hypobromite to give Methyl bromide and $ 5 - Hydroxy - 3 - pentanone $ . So, the product A according to reaction is $ 5 - Hydroxy - 3 - pentanone $ .
Let's see the second reaction in which product A reacts with hydronium ion; in an oxidation reaction the alcohol is converted to carboxylic acid. The reaction taking place here is written as
In above reaction 5-hydroxy-2-pentanone undergoes oxidation reaction to form $ 3 - Oxopentanoicacid $ . So, the product B according to question is $ 5 - Hydroxy - 3 - pentanone $
Let's see the last reaction in which product B undergoes strong heating to remove carbon dioxide. It is also known as the decarboxylation reaction. the reaction taking place here is written as
In above reaction $ 3 - $ Oxopentanoicacid undergoes decarboxylation reaction in strong heating conditions to form Carbon dioxide and $ {\text{n}} - butanone $ . So, according to the question the product C is $ {\text{n}} - butanone $ .
Note :
Carefully observe the position of the functional group while writing a reaction because it is necessary for the product formation. Also pay attention to the conditions in which the reaction is carried out because it can affect the reaction.
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