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The compound (C) is:
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Answer
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Hint :The compound given here is $ 5 - Hydroxy - 3 - hexanone $ which is treated with Sodium hypobromite to give product A which then is treated with hydronium ion to give product B. Product B is heated to obtain product C. we will see each reaction to understand the process and identify the products formed from each of the reaction.

Complete Step By Step Answer:
In the first reaction $ 5 - Hydroxy - 3 - hexanone is treated with Sodium hypobromite it will remove a methyl group and form alkyl halide and Sodium Hydroxide. The reaction taking place here is written as
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In the above reaction $ 5 - Hydroxy - 3 - hexanone $ reacts with Sodium hypobromite to give Methyl bromide and $ 5 - Hydroxy - 3 - pentanone $ . So, the product A according to reaction is $ 5 - Hydroxy - 3 - pentanone $ .
Let's see the second reaction in which product A reacts with hydronium ion; in an oxidation reaction the alcohol is converted to carboxylic acid. The reaction taking place here is written as
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In above reaction 5-hydroxy-2-pentanone undergoes oxidation reaction to form $ 3 - Oxopentanoicacid $ . So, the product B according to question is $ 5 - Hydroxy - 3 - pentanone $
Let's see the last reaction in which product B undergoes strong heating to remove carbon dioxide. It is also known as the decarboxylation reaction. the reaction taking place here is written as
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In above reaction $ 3 - $ Oxopentanoicacid undergoes decarboxylation reaction in strong heating conditions to form Carbon dioxide and $ {\text{n}} - butanone $ . So, according to the question the product C is $ {\text{n}} - butanone $ .

Note :
Carefully observe the position of the functional group while writing a reaction because it is necessary for the product formation. Also pay attention to the conditions in which the reaction is carried out because it can affect the reaction.