
The composition of a sample of wustite is $F{{e}_{0.92}}O$. What percentage of iron is present in the form of Fe(III)?
A. 5%
B. 7.08%
C. 15.05%
D. 23.60%
Answer
523.2k+ views
Hint: Wustite is a mineral form of iron oxide found with meteorites and native iron. It is grey in color and gives a greenish tint while reflected. It is found in the isometric-hexoctahedral crystal system which is opaque to metallic grains.
Complete answer:
We know that in pure form of iron oxide represented by the chemical formula$FeO$, iron and oxygen are present in the ratio 1 : 1.
However we can also conclude that here number of $F{{e}^{2+}}$ present is given i.e. 0.93 and we can say that number of \[F{{e}^{2+}}\] ions missing will be 0.07.
This concludes that each \[F{{e}^{2+}}\] ion has 2 positive charge thus the total number of charge due to missing \[F{{e}^{2+}}\] ions will be \[0.07\times 2=0.14\]
Now, to maintain electrical neutrality these 0.14 positive charges are compensated by the presence of \[F{{e}^{3+}}\] ions.
Now we know that replacement of one \[F{{e}^{2+}}\] ion by one \[F{{e}^{3+}}\]ion will increases one positive charge i.e. 0.14 positive charge must be compensated by the presence of 0.14 \[F{{e}^{3+}}\] ions.
In an easy manner we can say that 0.93 \[F{{e}^{2+}}\] ions have 0.14 \[F{{e}^{3+}}\]ions.
Thus 100 \[F{{e}^{2+}}\] ions have = \[\dfrac{0.14}{0.93}\times 100=15.05%\].
Thus, option C is the correct answer.
Note:
Wustite was an important component in the past times like in ancient times like when blacksmithing was performed using a charcoal forge then deep charcoal pit in which the steel or iron was placed which provides a highly reducing, virtually oxygen-free environment, and produces a thin wustite layer on the metal.
Complete answer:
We know that in pure form of iron oxide represented by the chemical formula$FeO$, iron and oxygen are present in the ratio 1 : 1.
However we can also conclude that here number of $F{{e}^{2+}}$ present is given i.e. 0.93 and we can say that number of \[F{{e}^{2+}}\] ions missing will be 0.07.
This concludes that each \[F{{e}^{2+}}\] ion has 2 positive charge thus the total number of charge due to missing \[F{{e}^{2+}}\] ions will be \[0.07\times 2=0.14\]
Now, to maintain electrical neutrality these 0.14 positive charges are compensated by the presence of \[F{{e}^{3+}}\] ions.
Now we know that replacement of one \[F{{e}^{2+}}\] ion by one \[F{{e}^{3+}}\]ion will increases one positive charge i.e. 0.14 positive charge must be compensated by the presence of 0.14 \[F{{e}^{3+}}\] ions.
In an easy manner we can say that 0.93 \[F{{e}^{2+}}\] ions have 0.14 \[F{{e}^{3+}}\]ions.
Thus 100 \[F{{e}^{2+}}\] ions have = \[\dfrac{0.14}{0.93}\times 100=15.05%\].
Thus, option C is the correct answer.
Note:
Wustite was an important component in the past times like in ancient times like when blacksmithing was performed using a charcoal forge then deep charcoal pit in which the steel or iron was placed which provides a highly reducing, virtually oxygen-free environment, and produces a thin wustite layer on the metal.
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